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I thought so too.

But the question did not say at least one person passed, it said only one person passed. This means that S,G passing but E failing is not a desirable outcome. Are you sure this doesn't effect the answer? Is the textbook answer incorrect?

The answer in the back of the book is \frac{5}{17}. Isn't the sample space, or the number of possible outcomes reduced when one person, and only one, must pass? Question 16c, 10C Cambridge 3U HSC for reference.

I struggle with this topic, though I'm trying to get better. I'd appreciate it if you could show me the working for this question: $Sophia, Gabriel and Elizabeth take their driving test. The chances they pass are $\frac{1}{2}$, $\frac{5}{8}$, and $\frac{3}{4}$ respectively. If only one of them...

I am 90% sure this question is wrong, but I wanted to post it here just in case I'm wrong. $Show that a polynomial with leading term $-x^3$ and a double root at $x=1$ has another root at point where $x>1. This is from Margaret Grove's Preliminary Maths in Focus 3 Unit textbook - 12.5 Q20. I...

Re: HSC 2015 3U Marathon It's not the site's fault, it's codecogs'.

$The expansion of $(x+y)^4$ is $1x^4y^0+4x^3y^1+6x^2y^2+4x^1y^3+1x^0y^4\\$Therefore, the middle term is: $6x^2y^2\\$Now we sub in our x and y, which are $2x$ and $-4$ respectively.$\\6\times(2x)^2(-4)^2=384x^2

Lucky I bought that one after yesterday!

Just did my 3U paper today. It was much harder than any other past paper I had ever done.

Re: Year 11 Mathematics 3 Unit Cambridge Question & Answer Thread I don't think you've missed any solutions.

Yeah, I've learnt that rule. This makes sense now.

I am so fucking done with this textbook.

Why wouldn't the first part be (n-k+1)! ? The number of "things" being arranged is n-k (the amount of people not in the group) and one more, the group itself. For example, if you have a 5 people with 3 of those people in a group, you have the two people not in the group, and the group itself...

You're going to love this... MIF. The only reason I'm using it is because Cambridge doesn't seem to have a P&C section.

Are you sure? The textbook says 126.

Would you please explain your reasoning for this?

Sorry, the answer to the third question is given as 126 in the textbook.

That seems logical, the quantity of numbers about 30 000 should be less than the total quantity of numbers. I believe it should be \frac{3\times4!}{2!}, which is equal to 36, the same as your calculation. The textbook definitely give 72 as the correct answer, however, at this stage I guess it's...

Hey everyone, please explain how to do these... 1. Numbers are formed from the digits 1, 2, 3, 3, and 7 at random. In how many ways can they be arranged to form a number greater than 30 000? (Answer is 72). My thinking: In that question, I understand that the first number must be a 3, 3...

Make a new thread, people wont notice it here.