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  1. Z

    HSC Mathematics Marathon

    Yep, I already see where I went wrong, namely leaving tan 2x out of there somewhere (which I'm assuming was important). Stuff this, I'm doing it on paper, scanning it and posting the image. Can't read my own typing...
  2. Z

    HSC Mathematics Marathon

    why thank you. I'm only new at it, that's why all the fractions are still in x/y form for instance
  3. Z

    HSC Mathematics Marathon

    \int\sec^3 2x\,dx = \int\sec^2 2x sec 2x\,dx = 1/2\int\(1 - tan2x) sec 2x\,d 2x = -1/2(1/2 sec 2x) + 1/2\int\sec 2x\,dx + C = -1/4sec 2x + 1/2(x sec 2x - \int\ x \,d(sec 2x)) + C = -1/4sec 2x + (x sec 2x)/2 - 1/2(sec 2x (x^2)/2) + C = -1/4sec 2x + (x sec 2x)/2 - x^2 sec 2x = sec...
  4. Z

    HSC Mathematics Marathon

    Respect...
  5. Z

    Joke Answers in HSC

    An essay accounting for the decline of living conditions under the rule of Stalin, involved a long, in depth discussion of how if Dr. Phil was there, he would have been able to talk everybody through it
  6. Z

    Simple Complex Numbers Q

    Same way cis(2pi/3) is one of the points on the unit circle z^3 = 1
  7. Z

    Imaginary Numbers

    It's not really a plane of reality. More its a graphical interpretation of complex numbers, which is why you can't have a complex number locus. RULE 1 of Complex Numbers: They cannot be graphed
  8. Z

    How would you sketch this?

    wouldn't: arg [(1+i)z] = arg[z] + arg[iz] ???
  9. Z

    another complex numbers question

    Complex numbers are always so much easier if you use the Argand Diagram, particularly these questions. Here's a starter:
  10. Z

    Dropping Ext. 2?

    70% is a great mark. In the HSC, a raw mark of around 60/120 will get you a 90+ The exam is designed so you can't get full marks.
  11. Z

    Complex locus question

    I wasn't aware that you could have loci on the imaginary axis, just vectors.
  12. Z

    HSC Mathematics Marathon

    Slightly unrelated, but ohexploitable, is your avatar from Gossip Girl? Also, as we have an absence of questions: If In = (Integral from 1 to 0) x^n tan(inverse)x dx, n = 0, 1, 2, ... Show that In = 1/(n+1) * π/2 - 1/[n(n+1)] - (n-1)/(n+1) * I(n-2), n = 2, 3, 4, ... Sorry, don't know latex
  13. Z

    Maths Extension 2 Students

    No way, curve sketching is so easy. You just have to remember what each does and you're set. Hating integration, don't mind complex numbers Graphs > Complex Numbers > Conics > Volumes > Harder Ext. 1 > Polynomials > Integration Haven't done mechanics yet
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