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HELP ! This question looks so easy but yet i cant do it, i know i am over compliccated it. Defrentiate ln ( Sin^-1 x) I remember got something to do with "u", i used u = Sin^-1 x and du/dx = 1 / square root 1 - x square. then i am stuck . . defrentiate ln x , you get 1/x . . soo...

Well whats the answer? Here is a logical "guess" Since A , B , C have an elvation of 26 , 28 , 30. "Assume" the height of the rock increase steadily . ( Since the elvation angle is increasing . . the height of the rock increase from different angle . . if u know what i mean ) . And therefore...

Hello people :D I'll get straight to the point :D Heres my ranking overall ranking ESL Enlish- ranking 1/5 Physics - ranking 3/21 Chemistry - ranking 4/32 3 unit maths - ranking 2/35 4 unit maths - ranking 1/9 With these rank, would it be save to assume a 90+ UAI ? btw...

For the above questions: Question: A particle moves on the x axis with velocity v given by v = (x + 1)<SUP>2</SUP>. Initially the particle is at the origin. Find the initial acceleration. v = (x+1)^2 (v^2)/2 = ((x+1)^4 )/2 d(v^2)/2 / dx = 2(x+1)^3 when x = 0 t = 0. a = 2(x+1)^3 (Sub...

I got this out of the 4 unit cambridge book on page 106. They said . . "The hyperbola xy = c square thus has eccentricity e= root 2, foci S(c root 2, c root 2) and S'( - c root 2, - c root 2 ) , directrices x + y = plus or minus c root 2." hope this answers your questions.

I've asked my teacher , what my trials paper is , cuz its not the independent trial paper nor the CSSA trials. And she said its the Westen region one. . . have any one done this for their trails ? whats your mark , and the highest mark at your school ?

:P thx for the reply , but i have already finished t he questiosn :P thx any way :D

i think my one was the independent trials, since its not the CSSA one, did alright in it, i am surpriced that my 4 unit maths mark is actually higher then my chemistry and physics mark . . . . btw i got 75% in 4u , and 74 in chem and 71 in physics = = which is pretty shit

show (3^4n ) minus 1 is divisible by 80 for all positive intergral value of n Need helpp :P mental blockage >_> any one give me a pump :D ? oh sheeeze lol, right after this post , i found out how to do it lol . . . For the last bit, K= K +1 , u will get (3^4(k+1)) -1 = (3^4 times...

what i heard from the teacher is that , there will be no difference if we swap positive and negative now , since we know it , its just the other way around. So that they are just too lazy and cant be bothered to change it , and named it the convention current. lol

althought i dont quite understand all the working out , but look at the first equation . . (k+1)(k+2) . . . . = (something) . . and the next one where they subbed k = k + 1 . . . soo the (k +1) before , became (k + 2 ) . . soo they introduced the (k+1)/(k+1) . . . which is equal to one , and...

mm. . for ii) 252km/h = 252000m / 3600s = 70m/s . . . there is a quicker way , its 252km/h divide by 3.6 = 70m/s . . ( dont ask me why divide by 3.6 lol . . i just know it that way lol ) for iii) since horizontal component is constant , dont worry about it. Thus theres only gravity force ...

:hammer: :hammer: oooo , soo that means i am not doing the CSSA tirals yeah . . ? hurray~~~ :hammer: :hammer:

Same as title, i am doing my extension 1 maths trial this friday , and i wonder if its the CSSA tirals . Is everyone doing their CSSA tirals on friday ? If so i am stuffed . . . i heard CSSA trials papers are hard . . .:(

Elllo ~ i do chem tooo :D glad that the CSSA paper wasnt too horrible :D

I cant wait till HSC finishes . . i think i have already pushed myself too hard that i am exhausted to even look at my physics book :p and now i am looking at the question , how advance technology helps us with the understanding of space . . things like that . . . i think they mean telescopes= =?

MEEE MEEEEEEEEEEEEEEEEEeeeeeeEEE. I am freaking out sooo badly, physics is my worsttttt subject , half yearlys i only obtain a mark of 63% i think . . and i heard that we are doing that CSSA physics trials paper tommrorw , i wish i can get above 70% . . . . OMGGGGGGGGGG:(

For x in terms of v , have u get things like , x = 1/2 ln (( g + 7.2 )/ g + 0.0005v^2)) ? thats what i got

MEME , i am totally screwed :D I went breserk and studies a whole lot on 4 unit , but came to thoughts i havent really touches 3 unit in like . . half a year . since the teacher dont do crap , and i dont know what to study for . . . soo yeah i am screwed . we are in the same boat :bomb:

Solve x^2/3 + x^1/3 -6 =0 use u = x ^ (1/3) sub it in , so u^2 + u - 6 = 0 (u + 3)(u-2) = 0 u=2 or u=-3 u = x ^ 1/3 x ^ 1/3 = 2 x = 8 or x ^ 1/3 = -3 x = - 27