Yes, my solution continued on from there.
cos x = 1/2 (0 ≤ x ≤ 2π)
when x = π/3; 2π - π/3 = 5π/3
cos x = -1/2
when x = π - π/3 = 2π/3, π + π/3, = 4π/3
.'. Series has a limiting sum for π/3 < x < 2π/3 and 4π/3 < x < 5π/3.
I recognise this is a simple solution, but what would another method be?