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Carla2003

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This is a dumb Q, I know, but whats the formula for the recation of barium hydroxide and nitric acid??? :)
 

mel85

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I think its
BaOH + HNO3 ----> BaNO3 + H20
(acid + base ----> salt + water)

Thats what I put anyway
 

Carla2003

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mine was more like monkees but I only had 2 water molecules. :(
 

t-i-m-m-y

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Originally posted by crazylilmonkee
Ba(OH)2 + 2HNO3 --> Ba(NO3)2 + 4H20
monkeys is correct....cept theres not that many waters i don't think it shoul be 2 water moleclues.. oh and i wrote + heat on the end.. i hope thats okay
 

hipsta_jess

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Originally posted by mel85
I think its
BaOH + HNO3 ----> BaNO3 + H20
(acid + base ----> salt + water)

Thats what I put anyway
Originally posted by Viper
not balanced
y isnt it balanced? i cant see anything wrong with it..
 

braindrainedAsh

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Originally posted by mel85
I think its
BaOH + HNO3 ----> BaNO3 + H20
(acid + base ----> salt + water)

Thats what I put anyway
Crap! I put this too.... for some reason I thought Ba was in group one, even though I know it is in group 2!!!! Silly silly me!!!! *shakes head*
 

Carla2003

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I know its not 2 water molecules, I made a stupid mistake, some how!!!!!!!!!!!!!!!!!!!!
How the hell do u guys remember all your answers, like the concentration??????????????
 

enemy

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Originally posted by Carla2003
I know its not 2 water molecules, I made a stupid mistake, some how!!!!!!!!!!!!!!!!!!!!
How the hell do u guys remember all your answers, like the concentration??????????????
No, you r rite,Carla,it's 2 H20.Look at the eq again and u should work it out.I don't remember te concentration.
 

Exeter

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although
BaOH + HNO3 ----> BaNO3 + H20
is balanced, BaOH isnt corrrect as Ba is 2+ and OH is 1-
therefore what i believe is correct is
Ba(OH)2 + 2HNO3 ----> BaNO3 + 2H20

so that kinda complicated things just a lil when using the equation
(CaVa)/S = (CbVb)/B
 

hipsta_jess

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Originally posted by Exeter
although
BaOH + HNO3 ----> BaNO3 + H20
is balanced, BaOH isnt corrrect as Ba is 2+ and OH is 1-
therefore what i believe is correct is
Ba(OH)2 + 2HNO3 ----> BaNO3 + 2H20
to start off i had the Ba(OH)2 one, and then i couldnt be bothered balancing it, then i noticed the BaOH one was already balanced, so i thought that was what they wanted, so thats the one i used
*damn valencies*
 

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