2001 HSC question 8 (1 Viewer)

[rawker]

Can someone please do this question, with working. I keep getting the wrong answer.. Thanks

The burning of sulfur can be described by the following equation:

S_(s) + O_{2 (g)} --> SO_{2 (g)}

What volume of sulfur dioxide will be released at 25^oC and 101.3 kPa when 8.00 g of sulfur is burnt?

 

[miss india]

haha calculations!
sorry cant help....
i need to c the answer too!!

 

[Monstar]

Not sure if this is right...

Mols of sulfur= m/M
=8 grams/ 32.07
=0.249 mol

Now

Mol of unknown (SO2)/ Mol of known (S)=1/1
We know that the moles of sulfur is 0.249 there fore the mole of SO2
=1x 0.249
=0.249

Now volume is just
=no. of moles x the volume of 1 mole at 101.3kPa
=0.239 x 24.79
=6.1975 L

I think its right.. i dunno

 

[rawker]

Yeah. Well it is close enough, the answer is 6.12L so it is just dependant on your accuracy.
Thanks