Honestly you guys got close but did not quite solve it. Some got it right but by the wrong way, therefore invalid. Some just got it wrong straight out. What I mean is it is still wrong if you get the right answer using the wrong method. I would like once again show the original question which was a multiple choice format
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Anna walks to school in 20 minutes. Anna can cycle to the school in 5 minutes. How much faster can Anna cycle than walk?
B 3
C 4
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I keep only 2 reasonable choices here. What it means is that you only need to guess. I suppose you either pick B or C. And if you hit what the author had in mind, you win. Otherwise you lose. I change "How much faster" to "How many times faster" after I see the ambiguity. Just by looking at the choices given, I know that the question is asking "How many times faster" rather than a pure "difference" in speed which could not be determined at all when the distance is not provided. It is clearly poor English wording. So I changed the question to "How many times faster can Anna cycle than walk?" just to remove the obvious ambiguity/fault. So now we have only one clear question to answer.
So the poor kids facing this selective school test had to pick B or C. Only one is right. When I asked people to solve it, even the ones that got the right result got it wrong because invalid reasoning was used. And this shows the limitation of multiple choices. You cannot show that you understand the matter. You cannot show that you think the author of the question got it wrong. In this case I think the author got the idea and answer right, but the person used bad wording. So I altered the wording to clear that up.
I just want to give more people a chance to comment. In my solution I will first eliminate the wrong reasonings that people have been trapped using proof by contradiction. Then I will solve the only left over interpretation of the question by algebraic method to show how algebra can hit it right on the head and clear the confusion once for all. I think when you set out to completely solve a problem, even a simple problem can become quite a challenge.
First, I want to remove the wrong reasonings
1/ You can wrongly use 20/5 = 4. Your answer will be 4x but it's wrong. The question is referring to speed, you try to solve it by a ratio of time. This is a disconnection here. You cannot validly jump between speed and time without showing a valid connection
2/ You can translate to speed and still get it wrong. Assuming the distance is D
D/5 divided by D/20 = D/5 x 20/D = 20/5 = 4
So the answer is 4x speed which is wrong. Why?
Let's imagine that cycling time is same as walking time, hence the speeds are also the same. Just pick any number say 5 minutes
D/5 divided by D/5 = D/5 x 5/D = 1
Now you have the answer "Anna can cycle 1 time faster than walk". This is clearly a contradiction when the time and speed are the same. People have made a mistake by leaving the word "faster" out.
Clearly, there is a big possibility is that the right answer is 3x
1/ I will not accept 3x as the valid answer if you arrive at 3x this way
20 - 5 = 15 (the difference in times)
15 / 5 = 3
While the answer (3x) is right and the reasoning seems on the right track, it fails to address the fact that the question is about speed, not time. As speed is inversely proportional to time, you really blow it!
2/ Therefore the correct answer must be calculated from looking at the difference in speeds and it is in term of speed. And here it is in algebra
Let D be the distance
Let Sw be the speed of walking
Let Sc be the speed of cycling
Let Tw be the time for walking
Let Tc be the time for cycling
1) Sw = D/Tw = D/20
2) Sc = D/Tc = D/5
The difference in speed between cycling and walking is Sc - Sw
3) Sc - Sw = D/5 - D/20 = 4D/20 - D/20 = 3D/20 = 3 x D/20
Now look at step 1 and 3, we know D/20 is Sw, we derive
4) Sc - Sw = 3 x Sw
Look at the question again "How many times faster can Anna cycle than walk?"
Equation 4 clearly shows the answer. The difference in speed between cycling and walking is exactly 3 times the speed of walking. In correct English comprehension, this "difference in speed" is the "faster" bit the question is asking.
BTW: a simpler problem that illustrates the exact same English comprehension is
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Anna has 4 dollars. John has 1 dollar. How many times more money does Anna has than John?"
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If you solve it by 4/1 = 4, you are screwed! because using same method, if both of them has 1 dollar each. You end it up doing 1/1 = 1. So Anna has 1 time more money than John when, in fact, they have same money! That's a contradiction. You have to solve it by (4-1)/1 = 3 because of the word "more".
I hope this whole exercise shows that we need the clarity of reasoning, the accuracy and the completeness when we are serious about problem solving.
So many people were stumped by this question regardless of their qualification and age! The habit to rush and avoid critical thinking screw us all.
---
Anna walks to school in 20 minutes. Anna can cycle to the school in 5 minutes. How much faster can Anna cycle than walk?
B 3
C 4
---
I keep only 2 reasonable choices here. What it means is that you only need to guess. I suppose you either pick B or C. And if you hit what the author had in mind, you win. Otherwise you lose. I change "How much faster" to "How many times faster" after I see the ambiguity. Just by looking at the choices given, I know that the question is asking "How many times faster" rather than a pure "difference" in speed which could not be determined at all when the distance is not provided. It is clearly poor English wording. So I changed the question to "How many times faster can Anna cycle than walk?" just to remove the obvious ambiguity/fault. So now we have only one clear question to answer.
So the poor kids facing this selective school test had to pick B or C. Only one is right. When I asked people to solve it, even the ones that got the right result got it wrong because invalid reasoning was used. And this shows the limitation of multiple choices. You cannot show that you understand the matter. You cannot show that you think the author of the question got it wrong. In this case I think the author got the idea and answer right, but the person used bad wording. So I altered the wording to clear that up.
I just want to give more people a chance to comment. In my solution I will first eliminate the wrong reasonings that people have been trapped using proof by contradiction. Then I will solve the only left over interpretation of the question by algebraic method to show how algebra can hit it right on the head and clear the confusion once for all. I think when you set out to completely solve a problem, even a simple problem can become quite a challenge.
First, I want to remove the wrong reasonings
1/ You can wrongly use 20/5 = 4. Your answer will be 4x but it's wrong. The question is referring to speed, you try to solve it by a ratio of time. This is a disconnection here. You cannot validly jump between speed and time without showing a valid connection
2/ You can translate to speed and still get it wrong. Assuming the distance is D
D/5 divided by D/20 = D/5 x 20/D = 20/5 = 4
So the answer is 4x speed which is wrong. Why?
Let's imagine that cycling time is same as walking time, hence the speeds are also the same. Just pick any number say 5 minutes
D/5 divided by D/5 = D/5 x 5/D = 1
Now you have the answer "Anna can cycle 1 time faster than walk". This is clearly a contradiction when the time and speed are the same. People have made a mistake by leaving the word "faster" out.
Clearly, there is a big possibility is that the right answer is 3x
1/ I will not accept 3x as the valid answer if you arrive at 3x this way
20 - 5 = 15 (the difference in times)
15 / 5 = 3
While the answer (3x) is right and the reasoning seems on the right track, it fails to address the fact that the question is about speed, not time. As speed is inversely proportional to time, you really blow it!
2/ Therefore the correct answer must be calculated from looking at the difference in speeds and it is in term of speed. And here it is in algebra
Let D be the distance
Let Sw be the speed of walking
Let Sc be the speed of cycling
Let Tw be the time for walking
Let Tc be the time for cycling
1) Sw = D/Tw = D/20
2) Sc = D/Tc = D/5
The difference in speed between cycling and walking is Sc - Sw
3) Sc - Sw = D/5 - D/20 = 4D/20 - D/20 = 3D/20 = 3 x D/20
Now look at step 1 and 3, we know D/20 is Sw, we derive
4) Sc - Sw = 3 x Sw
Look at the question again "How many times faster can Anna cycle than walk?"
Equation 4 clearly shows the answer. The difference in speed between cycling and walking is exactly 3 times the speed of walking. In correct English comprehension, this "difference in speed" is the "faster" bit the question is asking.
BTW: a simpler problem that illustrates the exact same English comprehension is
---
Anna has 4 dollars. John has 1 dollar. How many times more money does Anna has than John?"
---
If you solve it by 4/1 = 4, you are screwed! because using same method, if both of them has 1 dollar each. You end it up doing 1/1 = 1. So Anna has 1 time more money than John when, in fact, they have same money! That's a contradiction. You have to solve it by (4-1)/1 = 3 because of the word "more".
I hope this whole exercise shows that we need the clarity of reasoning, the accuracy and the completeness when we are serious about problem solving.
So many people were stumped by this question regardless of their qualification and age! The habit to rush and avoid critical thinking screw us all.