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A projectile fired at a speed of u and an angle of x to the horizontal (1 Viewer)

Karldahemster

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A projectile fired at a speed of u and an angle of x to the horizontal, reaches a
maximum height of H. When the same projectile is fired again at the same
angle with a new higher initial speed it reaches a new maximum height of 2H.

What is the new initial velocity in terms of u.
 

Powereaper

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That's for the new uy. But for the new initial velocity, which is root of uy2 + ux2, I got u times root (sin squared x plus 1).
Not sure if it's correct, so a confirmation would be appreciated.
 

InteGrand

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That's for the new uy. But for the new initial velocity, which is root of uy2 + ux2, I got u times root (sin squared x plus 1).
Not sure if it's correct, so a confirmation would be appreciated.






 
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InteGrand

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That's for the new uy. But for the new initial velocity, which is root of uy2 + ux2, I got u times root (sin squared x plus 1).
Not sure if it's correct, so a confirmation would be appreciated.
 

Powereaper

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Oh,got it now. I thought horizontal velocity was the same, until I realised the question didn't mention that. Thanks for the help.
 

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