Another question about permutations (1 Viewer)

goobi

Member
Joined
Oct 6, 2010
Messages
196
Gender
Male
HSC
2012
I'm really stuck with permutations which is the most difficult Extension 1 topic for me so yeah...
Okay so the question is:

Ten balls of identical size are placed side by side in a line. If 4 balls are read in colour, 3 are blue and 2 are green and 1 is white, in how many arrangements will there be a red ball at each end?

The answer is 1680 but I don't know how to get it.

Thanks for any help again!
 
Last edited:

Mature Lamb

wats goin on
Joined
May 14, 2009
Messages
1,117
Gender
Male
HSC
2010
Uni Grad
2015
Set 2 red balls, one at each end.

You will have 2 red balls, 3 blue balls, 2 green balls, and 1 white ball left to arrange in the middle.
 

goobi

Member
Joined
Oct 6, 2010
Messages
196
Gender
Male
HSC
2012
Set 2 red balls, one at each end.

You will have 2 red balls, 3 blue balls, 2 green balls, and 1 white ball left to arrange in the middle.
So, do you think this solution is correct?
8!2! / 2!3!2!2!
 

Users Who Are Viewing This Thread (Users: 0, Guests: 1)

Top