Answers To Difficult Questions (2 Viewers)

[mat2154]

pretty sure 18168 is correct

just wondering if someone could clear up the answers to the multiple choice questions:

1. A
2. D
3. B
4. C
5. D
6. C
7. D
8. C
9. A
10. C
11. B
12. A
13. A
14. B
15. C,B

thanks

 

[Forbidden.]

Oh great ... more silly mistakes ...

 

[fatemjay]

i got 18000 ppm, rounded off to 3 significant figures as they only gave 3 in the question.

for so2 i got 2.3 L rounded to 2 sig figs.

 

[nooj]

14 is d, b is talking abt atomic emission

 

[Bank$]

i totally agree with yiou the clorine is seen as an iniatiare for it breaks the ozone bond. a catayst lower rate of reaction it does play an actual role

Yeah im with u, in my trial i said it was a cataylist and got marked wrong lol

ummm i got like 600ppm for the Ag question ,,, haha think of it like this if we all wrong we all get scalled up

 

[Martyno1]

pretty sure 18168 is correct

just wondering if someone could clear up the answers to the multiple choice questions:

1. A
2. D
3. B
4. C
5. D
6. C
7. D
8. C
9. A
10. C
11. B
12. A
13. A
14. B
15. C,B

thanks

For 14 I put C (I don't even know if that's right?) because I thought B was explaining AES?
Apart from that I got the same as you except for one question which I made a very poor mistake in and realised when I walked out.

 

[fatemjay]

if Cl was an initiator it wouldnt be reformed.

they cant mark catalyst wrong, as they base it on textbooks - if one textbook says that its a catalyst they cannot mark catalyst wrong


EDIT: the answer to question 14 was (D)

 

[Martyno1]

if Cl was an initiator it wouldnt be reformed.

they cant mark catalyst wrong, as they base it on textbooks - if one textbook says that its a catalyst they cannot mark catalyst wrong


EDIT: the answer to question 14 was (D)

Yes it's a catalyst.. if you google "catalyst in breaking down of ozone" you'll see a lot of sites which agree.

 

[JoshyPutts07]

yeh i got 18045

..............but then i divided by 1000 coz im like "there is no way that can be correct", oopsies!............TRUST THE CALCULATOR NOT YOUR FRIKIN SENSE haha

and i got 2.3L for SO2 question



oh and did you people get 3mL for the KOH neutralisation?

 

[Bank$]

pretty sure 18168 is correct

just wondering if someone could clear up the answers to the multiple choice questions:

1. A
2. D
3. B
4. C
5. D
6. C
7. D
8. C
9. A
10. C
11. B
12. A
13. A
14. B
15. C,B

thanks

Yay i got all the same except for 14 which i put as D),,, i think we both got 9 wrong cause i found out after that Sodium Citrate is citric ACID with Na and i reckon the correct one is D cause CL is weak conjugate base HCL :mad1:


any 1 remember the precipitate question ? i think i got 3 as Pb solution, 2 as HCL, 1 as Na2CO3 and just deduced the last one

 

[iishjoo]

i got 18000 for the ppm of Cl too.

 

[fatemjay]

no 6mL, as H2SO4 is diprotic so the [H+] was double

 

[Pyros89]

Yeah im with u, in my trial i said it was a cataylist and got marked wrong lol

ummm i got like 600ppm for the Ag question ,,, haha think of it like this if we all wrong we all get scalled up

Yeah to be honest I thought it was an initiator, cause a catalyst does not play a part in the chemical reaction.

I though 14. was C, but Im prob wrong

 

[Martyno1]

Yay i got all the same except for 14 which i put as D),,, i think we both got 9 wrong cause i found out after that Sodium Citrate is citric ACID with Na and i reckon the correct one is D cause CL is weak conjugate base HCL :mad1:


any 1 remember the precipitate question ? i think i got 3 as Pb solution, 2 as HCL, 1 as Na2CO3 and just deduced the last one

No 9 is A because Ammonium Chloride is an acidic salt

 

[Martyno1]

yeh i got 18045

..............but then i divided by 1000 coz im like "there is no way that can be correct", oopsies!............TRUST THE CALCULATOR NOT YOUR FRIKIN SENSE haha

and i got 2.3L for SO2 question



oh and did you people get 3mL for the KOH neutralisation?

Yes I got 3mL

 

[fatemjay]

Think about the hydration of ethene ----- dilute H2SO4 catalyst

Step One: C2H4(g) + H2SO4(g) --> C2H5HSO4(g)
Step Two: C2H5HSO4(g) + H2O(g) --> C2H5OH(g) + H2SO4(g)
Overall: C2H4(g) + H2O(g) --> C2H5OH(g)

 

[NJMORTIMER]

Agreed, I think this is one of those cases where the simplest, most obvious answer is the correct answer. They showed the reforming of the chlorine radical for a reason and it fits with what the textbooks say (I've never seen it referred to as an initiator).

 

[Martyno1]

Yeah to be honest I thought it was an initiator, cause a catalyst does not play a part in the chemical reaction.

I though 14. was C, but Im prob wrong

I thought it was C too... I honestly thought the flame test wouldn't be enough to excite the electrons but I just realised it would be for most of them so it should be D.. damn!

 

[Pyros89]

I thought it was C too... I honestly thought the flame test wouldn't be enough to excite the electrons but I just realised it would be for most of them so it should be D.. damn!

But its called atomic absorption spectroscopy

 

[Bank$]

No 9 is A because Ammonium Chloride is an acidic salt

ohh gud then im safe lol damm now im definate i got the ppm one wrong i hope they mark like maths and c that i had the right working out lol

EDIT: if i did that is lol