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binomial question (1 Viewer)
- Thread starter live.fast
- Start date
ellen.louise
Member
ok...live.fast said:
=(x - (1/x))(x^2 - 2 + (1/x^2))
=x^3 - 2x + 1/x - x + 2/x - 1/x^3
=x^3 - 3x + 3x^-1 - x^-3
= - x^-3 + 3x^-1 - 3x + x^3
Ascending powers of x is just the order you arrange it in at the end.
P
pLuvia
Guest
Using binomial
(x-(1/x)3
=(3C0*(-1/x)3+3C1*x*(-1/x)2+3C2*x2*(-1/x)+3C3*x3)
Simplify
(x-(1/x)3
=(3C0*(-1/x)3+3C1*x*(-1/x)2+3C2*x2*(-1/x)+3C3*x3)
Simplify