Bionomial theorem (1 Viewer)

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physician

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Find the greatest coefficient in the expansion of (5-2x)12

what do u guys get...
 

Slidey

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There'll be 13 terms. You could just generate the coefficient of, say, the middle 4 and see which is greatest.

5^12 is pretty damn big.

It'd be something like:
5^12, 5^11 *-2*a, 5^10 *4*b, 5^9 *-8*c
So for it not to be the first term, a >2.5, for it not to be the 2nd term, b>25/4, c>125/8 et cetera.

At a guess, it might be the 8th term (since take a look at (1+x)^3 it is 1, 3, 3, 1 - obviously in the beginning the multipliers will cancel out the decreasing powers of 5, but the multipliers also increase as powers of 5 decrease, so... yeah I'd say somewhere in the middle 4)? I haven't covered binomial thoerem yet, though, so...
 
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Slidey

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(x+2)^4
=x^4+16x^3+24x^2+24x+16
(2x+3)^4
=16x^4+96x^3+648x^2+216x+81

My initial suspicion is correct: maximal coefficient is in the middle. The 8th coefficient.
 

Estel

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The method I'd use:
General term:
Tk = 12Ck.5^(12-k)2^k(-1)^k
for greatest coefficient, k must be even (so Tk>0)
Then solve Tk+2/Tk >1 where k=0,2,4,6,8,10
 

rama_v

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Couldnt you just use the formula method?
(n-r+1)/r .b/a >1 to determine r? Thats how I do these questions.
 

Estel

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No because every second term is negative, and the question asks for the greatest coefficient, not coefficient of greatest magnitude.
 

Slidey

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Not that it matters for this question.
 
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rama_v

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Estel said:
No because every second term is negative, and the question asks for the greatest coefficient, not coefficient of greatest magnitude.
ahh yes thats right. Thanks for clearing it up.
 

Estel

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Arvin: have you heard the song "The Elements"? :p
 

physician

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cool thanks guys... that was a question from my half yearly.... i was kind of lost in the exam because it was too long and i started freaking out... binomial theorem being my second strongest topic after circle geomtry, isn't all too difficult.. i guess i should revise it a little more...

but thanks for everyones help....
 
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