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Calculus (1 Viewer)

Thread starter excellence1
Start date Feb 26, 2016

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excellence1

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#1

A particle moves so that the rate of change of distance D over time t is given by R= 2e^t -1. If D=10 when t=0, find d when t=3

Nailgun

Cole World

#2

$\frac { dD }{ dt } ={ 2e }^{ t }-1\\ D=2{ e }^{ t }-t+C\\ Sub\quad (0,10)\quad where\quad (t,D)\\ 10=2+C\\ C=8\\ D=2{ e }^{ t }-t+8\\ Sub\quad t=3\\ D=2{ e }^{ 3 }-3+8\\ D=2{ e }^{ 3 }+5\quad at\quad t=3$

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