davidgoes4wce
Well-Known Member
Re: Year 11 Mathematics 3 Unit Cambridge Question & Answer Thread
![](https://latex.codecogs.com/png.latex?\bg_white y=-\sqrt{a^2-b^2x^2} )
![](https://latex.codecogs.com/png.latex?\bg_white $Convert to indices notation$ )
![](https://latex.codecogs.com/png.latex?\bg_white y=-(a^2-b^2x^2)^\frac{1}{2} )
![](https://latex.codecogs.com/png.latex?\bg_white \frac{dy}{dx}=-\frac{1}{2} (a^2-b^2x^2)^\frac{-1}{2} (-2b^2x) )
![](https://latex.codecogs.com/png.latex?\bg_white \frac{dy}{dx}=b^2x(a^2-b^2x^2)^\frac{-1}{2} )
![](https://latex.codecogs.com/png.latex?\bg_white \frac{dy}{dx}=\frac{b^2x}{(a^2-b^2x^2)^\frac{1}{2}} )
How do I differentiate this , using the chain rule , the constants are confusing me :
View attachment 32911