• Best of luck to the class of 2024 for their HSC exams. You got this!
    Let us know your thoughts on the HSC exams here
  • YOU can help the next generation of students in the community!
    Share your trial papers and notes on our Notes & Resources page
MedVision ad

Cambridge Prelim MX1 Textbook Marathon/Q&A (2 Viewers)

InteGrand

Well-Known Member
Joined
Dec 11, 2014
Messages
6,109
Gender
Male
HSC
N/A
Re: Year 11 Mathematics 3 Unit Cambridge Question & Answer Thread

Months. Not years.

You did not cater for the fact that interest is being compounded monthly in doing 1.135



Edit: I will give you a bit of the benefit of the doubt though - the question didn't explicitly say interest was compounded monthly either.
If it just says monthly repayments, then it means compounded monthly too (unless told otherwise).
 

appleibeats

Member
Joined
Oct 30, 2012
Messages
375
Gender
Male
HSC
2016
Re: Year 11 Mathematics 3 Unit Cambridge Question & Answer Thread

So in general if question have monthly repayments and they give interest rates per annum should you reckon that it is compounded monthly ??

Or is it just these questions are ambiguous??

Edit: Dont worry IG answered the Question
 
Last edited:

leehuan

Well-Known Member
Joined
May 31, 2014
Messages
5,805
Gender
Male
HSC
2015
Re: Year 11 Mathematics 3 Unit Cambridge Question & Answer Thread

If it just says monthly repayments, then it means compounded monthly too (unless told otherwise).
You could have questions where the repayments are per month but the compounding is annually. (Albeit it's a bit counter-logical because then you'd just have 12M which is why I've never seen it before.)

So in general if question have monthly repayments and they give interest rates per annum should you reckon that it is compounded monthly ??

Or is it just these questions are ambiguous??
In general the former

But it was most certainly ambiguous
 

InteGrand

Well-Known Member
Joined
Dec 11, 2014
Messages
6,109
Gender
Male
HSC
N/A
Re: Year 11 Mathematics 3 Unit Cambridge Question & Answer Thread

So in general if question have monthly repayments and they give interest rates per annum should you reckon that it is compounded monthly ??
Yes.

The "rate per annum" given needs to be divided by the appropriate number (in this case 12) to get the per-period interest rate.

I don't think it's actually ambiguous, it's just that these conventions aren't usually taught or emphasised properly in class, which can thus cause confusion among students.
 

InteGrand

Well-Known Member
Joined
Dec 11, 2014
Messages
6,109
Gender
Male
HSC
N/A
Re: Year 11 Mathematics 3 Unit Cambridge Question & Answer Thread

You could have questions where the repayments are per month but the compounding is annually. (Albeit it's a bit counter-logical because then you'd just have 12M which is why I've never seen it before.)
Yeah that's why I said "unless told otherwise".

I.e. If nothing else is said, the convention is what was required for this Q. (so in this case compounded monthly, and in general compounded per period of payment, which could be quarterly, semi-annually, or anything).
 
Last edited:

dlau

Member
Joined
Jul 1, 2015
Messages
39
Gender
Undisclosed
HSC
N/A
Re: Year 11 Mathematics 3 Unit Cambridge Question & Answer Thread



Could someone please help me with question 14 (e). It's from ex 7B


Sent from my iPhone using Tapatalk
 

Drongoski

Well-Known Member
Joined
Feb 22, 2009
Messages
4,254
Gender
Male
HSC
N/A
Re: Year 11 Mathematics 3 Unit Cambridge Question & Answer Thread

For (e): a = 6 or -6

vertex is V(a/2, -a2/4)

y = x2 - ax = x(x-a) = 0 at x = 0, a

.: axis of symmetry is: x = (0+a)/2 = a/2

at x = a/2, y = -a2/4

Hence the co-ords of the vertex

Here you find the gradient of the tangent = 0

So the tangent is a horizontal line: y = -a2/4 = - 9

so that a = 6 or -6


or

Since f(x) is a concave-up parabola, the tangent at the vertex is horizontal, so that this tangent has equation: y = -9
 
Last edited:

dlau

Member
Joined
Jul 1, 2015
Messages
39
Gender
Undisclosed
HSC
N/A
Re: Year 11 Mathematics 3 Unit Cambridge Question & Answer Thread



Help with q27 please.


Sent from my iPhone using Tapatalk
 

AfroNerd

New Member
Joined
Feb 21, 2016
Messages
24
Gender
Male
HSC
2017
Re: Year 11 Mathematics 3 Unit Cambridge Question & Answer Thread

So im not quite sure how to do questions b,c & d, and just out of curiosity how would you find how many 4 digit numbers are even.

img.png
 

leehuan

Well-Known Member
Joined
May 31, 2014
Messages
5,805
Gender
Male
HSC
2015
Re: Year 11 Mathematics 3 Unit Cambridge Question & Answer Thread

So im not quite sure how to do questions b,c & d, and just out of curiosity how would you find how many 4 digit numbers are even.

View attachment 33328
If you want even 4 digit numbers:

The last digit must be 2, 4, 6, 8 or 0. 5 options
The first digit can't be a 0. 9 options
The second and third digit can be anything.

Your answer: 9 x 102 x 5
___________
I think this is how to do it.


The number is greater than 4000: The first number cannot be a 3.

Case 1: First number is a 4
Remaining digits are 3, 4, 5, 6
There are 4! ways of arranging them.

Case 2: First number is a 5 or a 6. (Note: 2 favourable cases here.)
Remaining digits are 3, 4, 4, ?
There are 4!/2! ways of arranging them.

Answer: 4! + 2*4!/2!
 
Last edited:

Linh_N

New Member
Joined
Jul 9, 2016
Messages
1
Gender
Female
HSC
2016
Re: Year 11 Mathematics 3 Unit Cambridge Question & Answer Thread


I keep getting 5/26 for part (C). Can anyone explain how to work out the question?
 

HeroicPandas

Heroic!
Joined
Mar 8, 2012
Messages
1,547
Gender
Male
HSC
2013
Re: Year 11 Mathematics 3 Unit Cambridge Question & Answer Thread

@davidgoes4wce: Out of curiosity, what font is used for the first row of the table and "Total combinations"?
 
Last edited:

AfroNerd

New Member
Joined
Feb 21, 2016
Messages
24
Gender
Male
HSC
2017
Re: Year 11 Mathematics 3 Unit Cambridge Question & Answer Thread

If you want even 4 digit numbers:

The last digit must be 2, 4, 6, 8 or 0. 5 options
The first digit can't be a 0. 9 options
The second and third digit can be anything.

Your answer: 9 x 102 x 5
___________
I think this is how to do it.


The number is greater than 4000: The first number cannot be a 3.

Case 1: First number is a 4
Remaining digits are 3, 4, 5, 6
There are 4! ways of arranging them.

Case 2: First number is a 5 or a 6. (Note: 2 favourable cases here.)
Remaining digits are 3, 4, 4, ?
There are 4!/2! ways of arranging them.

Answer: 4! + 2*4!/2!
I don't understand how the answer wouldn't be 60 for b) since there are 5 numbers that can form 5 digits, which are greater than 4000. And the question doesn't say how many digits the number over 4000 can be.

However, I understand ur working for a 4 digit number greater than 4000
 

leehuan

Well-Known Member
Joined
May 31, 2014
Messages
5,805
Gender
Male
HSC
2015
Re: Year 11 Mathematics 3 Unit Cambridge Question & Answer Thread

I don't understand how the answer wouldn't be 60 for b) since there are 5 numbers that can form 5 digits, which are greater than 4000. And the question doesn't say how many digits the number over 4000 can be.

However, I understand ur working for a 4 digit number greater than 4000
Because maths in focus sucks.

That's a typo for 40000 and 50000 for b) and c) respectively.
 

AfroNerd

New Member
Joined
Feb 21, 2016
Messages
24
Gender
Male
HSC
2017
Re: Year 11 Mathematics 3 Unit Cambridge Question & Answer Thread

Because maths in focus sucks.

That's a typo for 40000 and 50000 for b) and c) respectively.
Ah so u were working it out for 40000 and not 4000?
 

AfroNerd

New Member
Joined
Feb 21, 2016
Messages
24
Gender
Male
HSC
2017
Re: Year 11 Mathematics 3 Unit Cambridge Question & Answer Thread

Okay tyvm I understand now. I was originally looking in the year 11 3u Cambridge book for permutations and combinations but couldn't find it.
 

Users Who Are Viewing This Thread (Users: 0, Guests: 2)

Top