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Carrotsticks' MX2 HSC 2013 Solutions (1 Viewer)

Carrotsticks

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what i meant was that for c)ii) didnt know how to show AE=.... using triangle ABD. so instead i used a different method where i had to expand sin(a+b). only afterwards did i realise that the next question c) iii) asked us to 'hence show sin(a+b) =sinacosb + sinbcosa.'

So i was wondering how many marks i would lose for using that trig identity.
In that case, probably 2.
 

RealiseNothing

what is that?It is Cowpea
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Great minds think alike.......

lol how did I stuff up like that. I wonder how many people in the state did this.
I'm wondering how many people in the state for question 5 of the multiple choice mistook as

I know my friend did.
 

RafH

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so...a mark of 58
What would that be scaled to?
 

panda15

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so no way i can scrape a 90?
If the markers are generous, i might be able to get 62.
Doubt you will be able to pull off 90. E4 will probably sit around 67.
 

Makematics

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Who wants to join my "lost more marks in question 11 than in question 16" crew?

Spewin' really
yep. first i did it in my trial, and again today. fk. it's always Q11.


i think this year's exam was very unique, in that it really favoured the top students, which is why you see people going on about how "half of the ruse and nsb cohort got 100" (im exaggerating, relax). at the same time it really punished rote learners, like the inequality question in Q16 was really quite standard yet it stumped a fair few people.
 

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