if I got 59/70 not counting any 'pity' marks is that a band 5?
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I think 59/70 is low E4.Just wanna thank you for making my day by confirming I'll get an e4<333 85 HSC mark was my goal all year, but 59/70 should equate to well over 90 shouldn't it?
Pretty sure that's a low Band 6.if I got 59/70 not counting any 'pity' marks is that a band 5?
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I think if you got alpha = 30, and justified that since alpha is positive then ydot>0 etc etc, then you would've gotten a CFP (carry from previous).would i get a carry on error if i got +30 instead of -30 for the angle in the projectile and so i said the particle was going up cos thats what my previous part gave me?
You would have gotten the mark for both (ii) and (iii).is it ok to just get pi/6 for the the projectile? I proved that time is after max height in (iii) hence it is down but I used y/x in part ii and still got the same magnitude so would I still get the marks?
Depends on the type of silly mistake (transcription error? carry from previous? etc) and where the question is located in the paper.If the q is a 1 marker and u make a silly mistake? will they give u the mark or not?
hmmm it's question 14 c i) I wrote 6C4 x (1/2)^6 *(1/2) BUT after i walked out because i was rushing i was thinking i may have wrote the multiply sign as a + sign instead.Depends on the type of silly mistake (transcription error? carry from previous? etc) and where the question is located in the paper.
Transcription error, you would've gotten the mark still. It is clear that you intended the multiply symbol.hmmm it's question 14 c i) I wrote 6C4 x (1/2)^6 *(1/2) BUT after i walked out because i was rushing i was thinking i may have wrote the multiply sign as a + sign instead.
I guess...For the projectile, since they didn't specify the orientation, is an angle of 150 degrees correct?
No, that is not correct because it means that the particle is flying backwards!For the projectile, since they didn't specify the orientation, is an angle of 150 degrees correct?
The question asked to find the remained no the quotient when it was divided by -3...I'm currently debating with someone as to whether Q1 was A or D. They think it's D because they gave x^3 -6x and not P(x)=x^3 -6x=0. That makes 0 sense to me, and I'm certain it was A because of Remainder theorem. To englishify my gibberish, he thinks that the remainder theorem doesn't apply to this question because they didn't equate it to 0 or something.... Any takers?
Oh right I see, I didn't see that you excluded the dots.hmm, but i just used y/x not ydot/xdot and got the answer pi/6 lol, so I prob lose 1 mark? or would they be nice and only consider the magnitude of the answer in ii as direction is in iii
The remainder is ALWAYS at most one degree less than the dividend (which is linear in this case). That means the remainder MUST be a constant.I'm currently debating with someone as to whether Q1 was A or D. They think it's D because they gave x^3 -6x and not P(x)=x^3 -6x=0. That makes 0 sense to me, and I'm certain it was A because of Remainder theorem. To englishify my gibberish, he thinks that the remainder theorem doesn't apply to this question because they didn't equate it to 0 or something.... Any takers?
No, you would have not lost a mark. Most likely that will align to 98 or 99.if i put the angle in degrees for projecitle would i lose a mark? also what would 67/70 scale/alingn to?