Chemistry Predictions/Thoughts (1 Viewer)

[skp_mp4]

yeah that's goo to hear, btw if you write a bit over the lines they gave you, will it still be marked? like do they scan the whole page??

The space within the lines is simply the area that is guaranteed to be scanned. Beyond that its uncertain if it will get scanned, hence why they ask to write inside it. However if it comes up in the scan they will mark it

 

[scaryshark09]

yeah that's goo to hear, btw if you write a bit over the lines they gave you, will it still be marked? like do they scan the whole page??

they scan the entire page

 

[p711]

there is literally no reason not to scan the entire page. scanning just the area with the lines surely is more tedious than just scanning the entire page. and it also has that like "dont write anything below this line" section, so i think that would make it explicit if they don't want you to write a bit outside of the lines

 

[SadCeliac]

there is literally no reason not to scan the entire page. scanning just the area with the lines surely is more tedious than just scanning the entire page. and it also has that like "dont write anything below this line" section, so i think that would make it explicit if they don't want you to write a bit outside of the lines

isn't your pfp the totw from last week

 

[p711]

isn't your pfp the totw from last week

nah i used to make totw predictions back in year 9, so i just whacked one of them as my pfp

 

[skp_mp4]

they scan the entire page

Yes but only the inside of the lines is like guaranteed to be inside, the outside has a chance to not be picked up

 

[Luukas.2]

doesnt 1,2-dichloroprop-1-ene fit cause you could assume Q might have a double bond and since doesnt specify excess cl2 it could only have 1 double bond being saturated also 1,2-dichloroprop-1-ene has 32 percent carbon by mass and has molecular ion peak at 114 it also has a fragment at 15 and 62?

No, it doesn't. 1,2-dichloroprop-1-ene could not be made by addition to an alkene.

Starting with propadiene (CH₂=C=CH₂) would yield 2,3-dichloroprop-1-ene assuming reaction with one equivalent (assuming that dienes like this react in this way), rather than to yield 1,2-dichloroprop-1-ene.

Starting with propyne (CH₃-CCH) would yield an addition product of 1,2-dichloroprop-1-ene from 1 equivalent, but the question specified that the starting material was an alkene, Q, so Q can't be propyne.

Further, if the product was 1,2-dichloroprop-1-ene, ClCH=CCl-CH₃, its parent ions would be:

• C₃H₄³⁵Cl₂^{+ .} at m/z = 3 x 12 + 4 + 35 x 2 = 110
• C₃H₄³⁵Cl₁³⁷Cl₁^{+ .} at m/z = 3 x 12 + 4 + 35 + 37 = 112
• C₃H₄³⁷Cl₂^{+ .} at m/z = 3 x 12 + 4 + 37 x 2 = 114

with relative intensities 9 : 6 : 1, yet the mass spectrum provided clearly shows the largest intensity molecular ion is at 112.

 

[Luukas.2]

there is literally no reason not to scan the entire page. scanning just the area with the lines surely is more tedious than just scanning the entire page. and it also has that like "dont write anything below this line" section, so i think that would make it explicit if they don't want you to write a bit outside of the lines

The "don't write in this area" section is where the booklets will be cut into individual sheets to feed into the scanner. This will be done by machine (take booklet, cut off margin and staple, feed sheet by sheet into scanner, produce image file of paper) so the scanned part will be as much of the page as is not cut off. No doubt some of the "don't write here" part does end up in the scans, but they do mean it that those parts may not be marked simply because no one will ever see them.

 

[carrotsss]

The "don't write in this area" section is where the booklets will be cut into individual sheets to feed into the scanner. This will be done by machine (take booklet, cut off margin and staple, feed sheet by sheet into scanner, produce image file of paper) so the scanned part will be as much of the page as is not cut off. No doubt some of the "don't write here" part does end up in the scans, but they do mean it that those parts may not be marked simply because no one will ever see them.

I don’t think they mean that part because it’s pretty explicit there, I think they mean the bit outside those corner things

 

[scaryshark09]

this question for example i wrote stuff in the blank white area which is fine. the entire page gets scanned. if you want proof, just look at sample student responses from previous years. it also just says don't write in the centre margin, and at the very bottom of the page, everything else is fine

 

[Retrodawn]

will I lose marks if I rounded my calculation of the ammonia back titration to 2sf instead of 4?

 

[swarley2345]

it depends on the marking criteria, for some questions they care about sig figs, for others they dont.

 

[kms1234]

Has there been no progress on getting the full paper. Everyday i dont see it, the more I die inside

 

[Interdice]

Here is another version with all the questions, but it is out of order

Outta curiosity. Where did you get the paper the first time? Cool if you don't want to answer

 

[lolcti]

Outta curiosity. Where did you get the paper the first time? Cool if you don't want to answer

Interdice does chem?! I thought you just talked ab depressing shit all day

 

[Interdice]

Interdice does chem?! I thought you just talked ab depressing shit all day

The only thing bigger than my Asian fetish is my hate for Chemistry

 

[Interdice]

Also for Q16. The answer is the compound with the bigger ksp. Right?

 

[ghreysantomy]

Also for Q16. The answer is the compound with the bigger ksp. Right?

Q16 was (B)
=> AgI precipitates out first as it has a SMALLER Ksp and so less of it needs to be added into a given volume before it begins to precipitate, compared to AgCl, whose Ksp is larger. The solutions, by PEAK, were posted on this thread a few days ago.

 

[Interdice]

Q16 was (B)
=> AgI precipitates out first as it has a SMALLER Ksp and so less of it needs to be added into a given volume before it begins to precipitate, compared to AgCl, whose Ksp is larger. The solutions, by PEAK, were posted on this thread a few days ago.

Thanks

 

[sneak11]

if for the 9 mark spectroscopy question i had put carboxyl accidentally instead of carbonyl but put (ketone) in brackets, is there a possibility i might still get that mark?