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Chemistryyyyy (1 Viewer)

beve

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This eludes me:

What mass of Hydrogen Gas is produced when 1.3g zinc reacts with excess hydrochloric acid? How much zinc chloride is prdouced?

So i have:

Zn + 2HCl > ZnCl2 + 2H

And there are 0.01988 moles of Zinc. (1.3/65.4)

But what do i do next?

:S
 

Continuum

I'm squishy
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beve said:
This eludes me:

What mass of Hydrogen Gas is produced when 1.3g zinc reacts with excess hydrochloric acid? How much zinc chloride is prdouced?

So i have:

Zn + 2HCl > ZnCl2 + 2H

And there are 0.01988 moles of Zinc. (1.3/65.4)

But what do i do next?

:S
The equation should be H2, not 2H.

So the equation is: Zn + 2HCl > ZnCl2 + H2

Since there are 0.01988 moles of Zn, according to the equation, it will also produce that many moles of ZnCl2. This is because 1 mole of Zn reacts with excess HCl to produce 1 mole of ZnCl2 and 1 mole of H2 - basically the numbers in front of the equation. So if it's only 0.01988 moles of Zn, the reaction can only produce 0.01988 moles of ZnCl2 and 0.01988 moles moles of H2.

Now that we found out that 0.01988 moles of H2 are produced, all we have to find out is the mass. Basically, find the weight of 1 mole of H2 by adding the weight of two Hs. After that, just go 0.01988/1 and times that by the formula weight of H2 since you only want to find out the weight of 0.01988 moles, not 1 mole.
 

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