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Joshmosh2

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Two chords AB and CD intersect within a circle at X. Prove that angle AXC is equal to the sum of the angles subtended at the circumference by the minor arcs AC and BD.
 

aDimitri

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By constructing lines AD & CB, we get the ever-so familiar butterfly shape. The angle from the minor arc AC is ACD, & the angle from the minor arc BD is BAD. Since the exterior angle of a triangle is equal to the sum of the two opposite interior angles, AXC = ACD + BAD
It's not a theorem, but it's a fairly short question
 

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