Can someone work B out please?Aerath said:a) In triangles XAC and XDB:
Angle X is common
Angle XAC = BDX (exterior angle of cyclic quad)
Angle XCA = XBD ( '' '' '' '' '' )
therefore, XAC and XDB are congurent (AAA)
b) Can't remember the exact name of the rule, but it's something like lines from exterior point...bleh, I can't remember it. But it's a circle geometry rule
c) Using the given formula
XA*XB = XC*XD
4*9 = x*(x+9)
x^2 + 9x = 36
x^2 + 9x - 36 = 0
(x-3)(x+12) =0 (x>0)
x = 3