Complex No. : Locus question (1 Viewer)

[Beaconite]

1) Need help with locus question




2) What is the in integration of : b sin (pie/b)x .dx


3)

 

[nightweaver066]

1. Going to leave it to others as i'm not 100% sure

2. \int bsin(\pi/b)x dx[/tex]





3.

A

 

[jeffwu95]

this is what i think 1 is

 

[nightweaver066]

What i think it is lol:

 

[asianese]

?? Is it dis?

 

[Aesytic]

i think nightweaver's one is right

 

[simskee]

nightweaver066's answer is correct

 

[Beaconite]

How'd youse do 1) ? :S

 

[jeffwu95]

ya my bad

 

[barbernator]

What the question is saying is.

The angle from (0,0) to a point is the same as the angle from (1,1) to a point. Now obviously that means that the gradient of the lines needs to be the same, and hence it is the region of the line y=x where x<0 or x>1

 

[Beaconite]

The highlighted part....someone explain me please

 

[barbernator]

View attachment 26337


The highlighted part....someone explain me please

when is the tan function undefined?

 

[Beaconite]

when is the tan function undefined?

90, 270

 

[Beaconite]

when is the tan function undefined?

But how do we know we have to consider tan inverse of infinity ?

 

[Beaconite]

dw i got it thnx anyway

 

[Beaconite]

two roots are conjugate pairs, and third root is found by 1+i + 1 -i + alpha =0

so alpha=-2

then i use product of roots to find p and i get p= -4

 

[Aesytic]

p is the sum of the roots 2 at a time; for product of roots, you're finding the value of q

 

[D94]

Since 1-i is a root of the polynomial, sub that into the equation. Expand it then equate real and imaginary parts. It should be p=-2 and q=4.