#### alcronin

##### New Member

- Joined
- Jul 25, 2011

- Messages
- 20

- Gender
- Female

- HSC
- 2013

Solve for Z:

1/Z = 1 + i + 2/(1-i)

Any help would be appreciated, thanks

- Thread starter alcronin
- Start date

- Joined
- Jul 25, 2011

- Messages
- 20

- Gender
- Female

- HSC
- 2013

Solve for Z:

1/Z = 1 + i + 2/(1-i)

Any help would be appreciated, thanks

- Joined
- Jul 12, 2011

- Messages
- 2,258

- Gender
- Male

- HSC
- 2012

I'll just give a few pointers and if you still need more help, then I'll write more:

Solve for Z:

1/Z = 1 + i + 2/(1-i)

Any help would be appreciated, thanks

1. Put the RHS all on the same denominator

2. Take inverses of both sides

3. Realise the denominator

4. Finished

- Joined
- Jul 25, 2011

- Messages
- 20

- Gender
- Female

- HSC
- 2013

- Joined
- Jul 25, 2011

- Messages
- 20

- Gender
- Female

- HSC
- 2013

Does this mean I can do the same for 2z/ (2+i) + 3-2i = (1-i)Z??

- Joined
- Jul 12, 2011

- Messages
- 2,258

- Gender
- Male

- HSC
- 2012

I didn't get that- I just did it very quickly so it might be wrong but I got z=(1-i)/4. Care to post your working?

- Joined
- Jul 25, 2011

- Messages
- 20

- Gender
- Female

- HSC
- 2013

= (1+2i-1+2)/(1-i)

= (2i+2)/(1-i)

= (1+2i)/(1-i) X (1+i)/(1+i)

= (2+2i+2i-2)/(1+1)

= 4i/2

= 2i

therefore, Z = 1/2i

Sorry for it being hard to understand, they don't have equation editors on here

- Joined
- Jul 25, 2011

- Messages
- 20

- Gender
- Female

- HSC
- 2013

- Joined
- Jul 17, 2012

- Messages
- 402

- Gender
- Male

- HSC
- 2013

deswa1 is a super hero