CSSA Trial Q (1 Viewer)

[krypticlemonjuice]

How do we do this question??

 

[howcanibesmarter]

So for the q14 one,
Since it is an uniform electric field, the forces at any point will be the same, thus acceleration will also be the same. Should be D.

As for the Q9,
Fc=Fg, since the centripetal force of m counteracts the weight force of the M
Therefore mv^2/r =Mg
Rearranging for M gives mv^2/rg

Please let me know if any of these you still dont understand/i got them wrong

 

[krypticlemonjuice]

So for the q14 one,
Since it is an uniform electric field, the forces at any point will be the same, thus acceleration will also be the same. Should be D.

As for the Q9,
Fc=Fg, since the centripetal force of m counteracts the weight force of the M
Therefore mv^2/r =Mg
Rearranging for M gives mv^2/rg

Please let me know if any of these you still dont understand/i got them wrong

Ahh I see yes you're right.

For 14, is that the full explanation as to why thats the answer or would there be more to it?

 

[carrotsss]

Ahh I see yes you're right.

For 14, is that the full explanation as to why thats the answer or would there be more to it?

that’s it