MedVision ad

Differential equations (1 Viewer)

HeeeHeee

New Member
Joined
May 4, 2022
Messages
8
Gender
Male
HSC
2022
Hi Guys. For part ii do we need to memorize the differential equation general solution
1652933925603.pngIf not how do we solve? Thanks


1652933868635.png
 

Masaken

Unknown Member
Joined
May 8, 2021
Messages
1,725
Location
in your walls
Gender
Female
HSC
2023
When I was taught this equation, we were taught how to solve it for fun, but it's quite long (I don't remember if my tutor said to memorise it or not, but my tutor told me it used ext 2 integration, so not sure). I would take a pic of my notes, but as I don't have them right now, here's the solution and how to get it: https://math.libretexts.org/Bookshe...Pdt=rP(1−PK,relative to the carrying capacity.

(Scroll down to 'Solving the Logistic Differential Equation')
 

pikachu975

Premium Member
Joined
May 31, 2015
Messages
2,739
Location
NSW
Gender
Male
HSC
2017
Hi Guys. For part ii do we need to memorize the differential equation general solution
View attachment 35637If not how do we solve? Thanks


View attachment 35636
ii)
Question says "HENCE" meaning you should use part (i).

dP/dt = P/30 * (10000-P)/10000
dP/dt = (1/30) * P(10000-P)/10000
dt/dP = 30 (1/P + 1/(10000-P)) using part (i)

Integrate:
t = 30 lnP - 30 ln(10000-P) + C
At t = 0, P = 1200
C = 30 ln8800 - 30ln1200

t = 30lnP - 30 ln(10000-P) + 30 ln8800 - 30ln1200
t/30 = ln(8800P/1200(10000-P))
e^(t/30) = 22P/3(10000-P)
30000 e^(t/30) - 3P e^(t/30) = 22P
P (22+3e^(t/30)) = 30000 e^(t/30)
P = 30000 e^(t/30) / (22 + 3e^(t/30))
 

cossine

Well-Known Member
Joined
Jul 24, 2020
Messages
627
Gender
Male
HSC
2017
When I was taught this equation, we were taught how to solve it for fun, but it's quite long (I don't remember if my tutor said to memorise it or not, but my tutor told me it used ext 2 integration, so not sure). I would take a pic of my notes, but as I don't have them right now, here's the solution and how to get it: https://math.libretexts.org/Bookshelves/Calculus/Book:_Calculus_(OpenStax)/08:_Introduction_to_Differential_Equations/8.4:_The_Logistic_Equation#:~:text=dPdt=rP(1−PK,relative to the carrying capacity.

(Scroll down to 'Solving the Logistic Differential Equation')
Cool website
 

Users Who Are Viewing This Thread (Users: 0, Guests: 1)

Top