hscishard
Active Member
Differentiate:
(x+5)^4
----------- = y
(x-3)
(x+5)^4
----------- = y
(x-3)
Take care when using the chain ruleThat'd be a function of a function and a quotient rule:
[(x+5)^4] / (x-3)
uv - vu/v^2
u = (x+5)^4
v = x-3
u' = 4x(x+5)
v' = 1
vu' - uv' / v^2
4x(x-3)(x+5) - (x+5)^4 / (x-3)^2
I believe that simplifies down/complicates up to:
f'x = (3x^4+28x^3-30x^2-900x-2125)/(x^2-6x+9)
This is probably as hard as it'll get with integration for 2UThx, thats what i got as well. I just thought it was too easy and there was a trick behind this question.
Glad i could help ^^I knew I got something wrong... well, looks like you helped two people anna!
* Differentiation lolThis is probably as hard as it'll get with integration for 2U
cerrection* Differentiation lol
Aha you can tell i'm not a morning person can't you? XD* Differentiation lol
*Correctioncerrection
The teacher's answer turned out to be (3x-17)(x+5)^3 / (x-3)^2. They factorised and simplified the "-4(x-3)(x+5)^3 - (x+5)^4 / (x-3)^2". God bloody coaching teachers.That'd be a function of a function and a quotient rule:
I believe that simplifies down/complicates up to:
f'x = (3x^4+28x^3-30x^2-900x-2125)/(x^2-6x+9)