e^f(x) graph (1 Viewer)

lolcakes52

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Not exactly. The Left hand side is easy, the zeros of f(x) get the y value of one. Concavity stays the same. The asymptote is infinity from the left and is an open circle at zero from the right. We observe that f(x) approaches to 1 as x approaches to infinity. So e^f(x) approaches e^1, or e.
 
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Not exactly. The Left hand side is easy, the zeros of f(x) get the y value of one. Concavity stays the same. The asymptote is infinity from the left and is an open circle at zero from the right. We observe that f(x) approaches to 1 as x approaches to infinity. So e^f(x) approaches e^1, or e.
means an open circle in this situation...
 

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