Elastic and Inelastic collisions - Question. (1 Viewer)

~shinigami~

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How would I show, using formulae and such to show that a collision is elastic or inelastic?

I know that an elastic collision conserves Kenetic Energy so would it be something like this:

½m1u12 + ½m2u22 = ½m1v12 + ½m2v22

Thank You in advance. :)
 

BigBear_25

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~shinigami~ said:
How would I show, using formulae and such to show that a collision is elastic or inelastic?

I know that an elastic collision conserves Kenetic Energy so would it be something like this:

½m1u12 + ½m2u22 = ½m1v12 + ½m2v22

Thank You in advance. :)
Well your right for the elastic collisions part the formula is right.
For inelastic collision you would have something similar:



½m1u12 + ½m2u22 = ½m1v12 + ½m2v22 + energy loss

I think this is how you do it. Its been a while since i have done this.

Hope is helps. :)
 

~shinigami~

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Thank You Big Bear for confirming the elastic collision formula and thank you for showing me the inelastic formula.

Also for inelastic, can I just use the elastic formula and show that initial KE does not equal final KE therefore inelastic?
 

zeropoint

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rama_v said:
In completely inelastic collisions, the masses stick together.
So the equation becomes

½m1u12 + ½m2u22 = ½(m1+m2)v2

This page is useful
http://hyperphysics.phy-astr.gsu.edu/hbase/inecol.html#c1
This equation is wrong. I think what you meant to say was that

m1u1 + m2u2 = (m1+m2)v

Kinetic energy is not conserved in an inelastic collision, whereas momentum is always conserved.
 

rama_v

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zeropoint said:
This equation is wrong. I think what you meant to say was that

m1u1 + m2u2 = (m1+m2)v

Kinetic energy is not conserved in an inelastic collision, whereas momentum is always conserved.
Oh oops yeah you are right. kinetic energy is not conserved but momentum is. Oh and I think momentum is ONLY conserved when the external forces on a system are negligeable, right?
 

~shinigami~

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Thanks for confirming that rama. :)

I was getting worried about using the wrong formula.
 

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