Electron in magnetic field question.... (1 Viewer)

dawso

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have this as one of many for a homework assignment, its past hsc (like...93 or something) anyway, i dont get any of the multiple choice answers....wat do u guys get

"an electron appears to be moving in a circular path of radius 10 cm in a plane perpendicular to a uniform magnetic field of 9.1 x10 ^-5 T. What is the instantaneous velocity of the electron"

and if ya dont mind, try some working,

cheers

-dawso
 

rama_v

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Maybe its like this
F = Bqv = mv^2/r equate them so you get Bq = mv/r
(9.1 x 10^-5) (1.6x10^-19)= (9.1 x 10^-31)v / 0.1
v = 1.6 x 10^6

Is that even right? lol its just a guess :|
 
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dawso

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ah geez, my bad, disregard my post, i know wat i did wrong :S
 

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