J juantheron Active Member Joined Feb 9, 2012 Messages 259 Gender Male HSC N/A Mar 30, 2023 #1 Proving the result

C cossine Well-Known Member Joined Jul 24, 2020 Messages 520 Gender Male HSC 2017 Mar 30, 2023 #2 Try proving n/ (n!)^(1/n) >2

T tywebb dangerman Joined Dec 7, 2003 Messages 1,403 Gender Undisclosed HSC N/A Mar 31, 2023 #3 It is also true for n=6. Induction proof. . Hence by the principal of mathematical induction, it is true for all integers Last edited: Mar 31, 2023

It is also true for n=6. Induction proof. . Hence by the principal of mathematical induction, it is true for all integers

J juantheron Active Member Joined Feb 9, 2012 Messages 259 Gender Male HSC N/A Mar 31, 2023 #4 cossine said: Try proving n/ (n!)^(1/n) >2 Click to expand... Thanks cossine. Using your hint , We use Stirling approximation So we have Last edited: Mar 31, 2023

cossine said: Try proving n/ (n!)^(1/n) >2 Click to expand... Thanks cossine. Using your hint , We use Stirling approximation So we have

J juantheron Active Member Joined Feb 9, 2012 Messages 259 Gender Male HSC N/A Mar 31, 2023 #5 tywebb said: It is also true for n=6. Induction proof. . Hence by the principal of mathematical induction, it is true for all integers Click to expand... Thanks Tywebb. I have tried like this way I am assuming So we have

tywebb said: It is also true for n=6. Induction proof. . Hence by the principal of mathematical induction, it is true for all integers Click to expand... Thanks Tywebb. I have tried like this way I am assuming So we have

synthesisFR Well-Known Member Joined Oct 28, 2022 Messages 2,639 Location North Korean Embassy, Russian Province Gender Male HSC 2023 Mar 31, 2023 #6 juantheron said: Thanks Tywebb. I am assuming So we have Click to expand... U need to stop pulling out the uni stuff for mx2 juantheron said: Using your hint , We use Stirling approximation So we have Click to expand... or this

juantheron said: Thanks Tywebb. I am assuming So we have Click to expand... U need to stop pulling out the uni stuff for mx2 juantheron said: Using your hint , We use Stirling approximation So we have Click to expand... or this