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Factorial question (1 Viewer)
- Thread starter kpad5991
- Start date
yanujw
Well-Known Member
Suppose you have n! that you want to express as the product of smaller factorials. Let the largest of these smaller factorials be k! e.g. in the above example n = 10 and k=7
n!/k! = n(n-1)(n-2)...(n-k+1)
For the example given, 10!/7! = 10 x 9 x 8 = 720
Then it is a matter of finding smaller factorial results that multiply to give this product. To make it easier, I reccomend trying values of k that are close to n at first.
1 set of solutions for this problem includes;
a) 7! x 6!
b) 2! x 4! x 47!
c) 4! x 23!
n!/k! = n(n-1)(n-2)...(n-k+1)
For the example given, 10!/7! = 10 x 9 x 8 = 720
Then it is a matter of finding smaller factorial results that multiply to give this product. To make it easier, I reccomend trying values of k that are close to n at first.
1 set of solutions for this problem includes;
a) 7! x 6!
b) 2! x 4! x 47!
c) 4! x 23!