# Fertiliser (1 Viewer)

#### horndog huang 2

##### Member

Hi all, i would like some to explain how to do this q and perhaps fertiliser questions in general. I just cant get my head around those. Thankd

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#### Suu

##### Member
It's a gravimetric analysis question.
I find that this website has explained how to do these fertiliser questions pretty well:
http://www.easychem.com.au/monitoring-and-management/manufactured-products/sulfate-experiment

Basically, Barium Chloride reacts with Sulfate to form Barium Sulfate, which comes in the form of a precepitate.
From there, Mass of Sulfate/ Mass of Barium Sulfate * Amount of Barium Sulfate = Mass of Sulfate. From there, you can find the percentage of Sulfate in the Fertiliser.
Cheers

Jesus

#### ProdigyInspired

$\bg_white mass\quad of\quad Fertiliser\quad =\quad 2.00g\\ mass\quad of\quad precipitate\quad =\quad 2.23g\\ \begin{matrix} Percentage\quad of\quad S{ O }_{ 4 }\quad in\quad BaS{ O }_{ 4 }\quad =\quad \frac { 96.1 }{ 233.4 } \\ =\quad 41.1174\% \end{matrix}\\ \begin{matrix} Mass\quad of\quad { SO }_{ 4 }\quad in\quad BaS{ O }_{ 4 }\quad =\quad \%\quad S{ O }_{ 4 }\quad in\quad Ba{ SO }_{ 4 }\times \quad Mass\quad of\quad BaS{ O }_{ 4 } \\ =\quad 2.23\quad \times \quad 41.1174\% \\ =\quad 0.918179 \end{matrix}\\ \begin{matrix} Percentage\quad of\quad S{ O }_{ 4 }\quad in\quad Fertiliser\quad =\quad mass\quad of\quad S{ O }_{ 4 }\quad /\quad mass\quad of\quad Fertiliser\quad \times \quad 100\quad \\ =\quad 0.918179\quad /\quad 2.00\quad \times \quad 100 \\ =\quad 45.908955\% \end{matrix}$