Find lim (x-->0) 5/sin3x (1 Viewer)

[enigma_1]

lim 5/ (sin3x)
x-->0

 

[ConorDevaney]

is it meant to be 5x/sin3x , because then the answer would easily become 5/3

 

[Carrotsticks]

is it meant to be 5x/sin3x , because then the answer would easily become 5/3

This.

 

[enigma_1]

omg that's why! Yeah sorry it does. I read the question wrong and wrote it down wrong and was like wtf this isn't working hahaha thanks!

But you wouldn't be able to do that question above anyway, right?

 

[Carrotsticks]

omg that's why! Yeah sorry it does. I read the question wrong and wrote it down wrong and was like wtf this isn't working hahaha thanks!

But you wouldn't be able to do that question above anyway, right?

Nope, you wouldn't. The limit doesn't exist.