• YOU can help the next generation of students in the community!
    Share your trial papers and notes on our Notes & Resources page

Finding functions (1 Viewer)

08er

Member
Joined
Dec 9, 2008
Messages
877
Gender
Male
HSC
2008
Given x^2 + y = 0, is y a function of x? Is x a function of y? How do you do this without vertical line test?
 

Iruka

Member
Joined
Jan 25, 2006
Messages
544
Gender
Undisclosed
HSC
N/A
We can rearrange the equation to y=-x^2

Then it is clear that this is function of x, not y.
 

08er

Member
Joined
Dec 9, 2008
Messages
877
Gender
Male
HSC
2008
thanks but how would you do it according to the definition of a function: that one input number is assigned to one output number....

how can u prove the functions?
 

Drongoski

Well-Known Member
Joined
Feb 22, 2009
Messages
4,254
Gender
Male
HSC
N/A
Given x^2 + y = 0, is y a function of x? Is x a function of y? How do you do this without vertical line test?

So y = - x^2 ( upside down parabola of y = x^2)

so x^2 = - y

Therefore x = +/- sqrt(-y) = 2 distinct value except for y = 0

i.e. for every nonzero y, x has 2 distinct values.

That means x is not a function of y, since to be a function of y, every value of y

must lead to one and only one value of x.
 

08er

Member
Joined
Dec 9, 2008
Messages
877
Gender
Male
HSC
2008
but wouldnt square rooting x^2 give us +/- x, and not just x?
 

Users Who Are Viewing This Thread (Users: 0, Guests: 1)

Top