**Re: MATH1231/1241/1251 SOS Thread**

Just saying, that's one way to confuse people. Explanation is not clear.=Int(Coshx+coshx*sinh^2x )

Since coshx*sinh^2x is of the form int(y'*y)

We can treat it as x^2 so int(x^2) is (x^3)/3

Thus Int(Coshx+coshx*sinh^2x )=sinhx+sinh^3x/3