MedVision ad

further rates of change (1 Viewer)

AFGHAN22

Member
Joined
Jun 10, 2005
Messages
73
Gender
Male
HSC
2006
a horizontal trough 10 m long, has a cross section in the shape of a right-angled isosceles triange, if water is poured in at the rate of 8m^3/min, at what rate is the water level rising when the depth of the water is 2m.

the answer is 1/5m/min but i got 2/5m/min
 

sasquatch

Member
Joined
Aug 15, 2005
Messages
384
Gender
Male
HSC
2006
yeah i did it and got the same answer as you! so i think your book is wrong..
 

alcalder

Just ask for help
Joined
Jun 26, 2006
Messages
601
Location
Sydney
Gender
Female
HSC
N/A
OK, so the volume of this trough:

If h is the height of the water and x is the length of the sides of the right isosceles triangle, the length of the top side of the trough is 2h.

Pythagorus says: x2 + x2 = (2h)2

2x2 = 4h2
x2 = 2h2

So, V = area of cross-section . length of trough

V = x2/2 x 10

V = 5x2 BUT x2 = 2h2

V = 10h2

dV/dh = 20h

When h = 2, dV/dh = 40 OR dh/DV = 1/40

dh/dt = dh/dV x dV/dt

= 1/40 x 8

dh/dt = 1/5 m/min
 

sasquatch

Member
Joined
Aug 15, 2005
Messages
384
Gender
Male
HSC
2006
haha yeah alcalder is right. What i think we all did (well i did this)

i got dv/dx = 20x, and dV/dt = 8 m^3/min

So dx/dt = (dv/dt) / (dV/dx) = 2/5x.

I did most of it in my head so i accidentally left out the x.

AFGHAN22 said:
at what rate is the water level rising when the depth of the water is 2m.
x = 2.

so dx/dt = 1/5

I think by putting that answer 2/5.. it kinda gave us a bias.. hehe
 
Last edited:

AFGHAN22

Member
Joined
Jun 10, 2005
Messages
73
Gender
Male
HSC
2006
can someone please draw up a diagram of this trough becuase i have difficulty understanding what it looks like....i understand how to do everything except i don't quite understand how x^2 +x^2=(2h)^2...as soon as someone can explain that then i can understand the question...but i think the main problem is how i think the diagram looks like..thanks for all your replies
 

Mountain.Dew

Magician, and Lawyer.
Joined
Nov 6, 2005
Messages
825
Location
Sydney, Australia
Gender
Male
HSC
2005
ur right AFGHAN22. main reason why we got 2/5 instead of 1/5 was because the f**ken diagram was wrong. attached are both the incorrect and the correct diagrams.

hope this helps AFGHAN22

alcalder, thank you for clarifying our mistakes :)
 

Users Who Are Viewing This Thread (Users: 0, Guests: 1)

Top