use xpq = ypr and the 2 right angles in the semicircle. Do a similar process to i for c2 and you end up with angle apx=angle rpcHow did u guys prove Q16(a)(ii)? Collinear one
Does 64/5 or something like that, maybe with a pi sound reasonable?This was a good paper, harder than last years.
Idk why there so many graph questions, it pissed me off because of how much time wasted. Hopefully they're not anal in marking it, also what did everyone get for the volume with the trapezium slices?
Also, I think a raw mark of 65ish would align to 90
You prove that one side had all the same angles with the other side and then you can say it is 180 degrees thus making <APC a straight line therefore collinearHow did u guys prove Q16(a)(ii)? Collinear one
I got 24 root 3 all over 5This was a good paper, harder than last years.
Idk why there so many graph questions, it pissed me off because of how much time wasted. Hopefully they're not anal in marking it, also what did everyone get for the volume with the trapezium slices?
Also, I think a raw mark of 65ish would align to 90
just no.You could have been a smart-ass for Q14 (a) (ii) and said that since x=1 is a root of multiplicity 3, three of the roots are 1, 1 and 1.
So two complex roots of P(x) are 1 and 1, since all real numbers are complex numbers =)
Lol. Would you get the marks for that?You could have been a smart-ass for Q14 (a) (ii) and said that since x=1 is a root of multiplicity 3, three of the roots are 1, 1 and 1.
So two complex roots of P(x) are 1 and 1, since all real numbers are complex numbers =)
wtf? since was there an induction Q?- Didn't even bother attempting 16b, got home and realised how easy i and ii were haha
- The plane mechanics question, parts 1 and ii, WTF?? Anyone get them out?
- Got cooked by induction
- Bad paper
I thought about that. But it specified the two complex rootsYou could have been a smart-ass for Q14 (a) (ii) and said that since x=1 is a root of multiplicity 3, three of the roots are 1, 1 and 1.
So two complex roots of P(x) are 1 and 1, since all real numbers are complex numbers =)
What induction?- Got cooked by induction
Perhaps used induction for 16 bi xDwtf? since was there an induction Q?
Haha of course not.Lol. Would you get the marks for that?
'The' means nothing to me =)I thought about that. But it specified the two complex roots