Part i was to find the IMMEDIATE amount, hence, you calculate how much was left from the 1st dose and you add it to the 10mL so it should be 10/3+10 unless we're wrong.
you are right for part i) as the question says amount of drugs right after second dose (somewhere on the lines of this) therefore at end of 1st 8hr period there will be 10/3 mL of drugs within patient (1/3 of drugs present at begining of 8hr period remains). therefore right after second dose, which is when 1st 8hr period ends, you have (10 + 10/3)mL of drugs! you should change your response to 'it's right 99% sure' (well thats what i believe) and for 13b) ii), i believe that is the bearings question, i got 333 degrees for that (seeing that most other people have this and including me, i believe that is quite solid evidence that 333 degrees is correct)
sorry to pop your bubble, but the question asked for nearest dollar therefore A60 = $44, 404superannuation q
A60 = 500(1.003)^60 + 500(1.01)(1.003)^59 + ... + 500(1.01)^58(1.003)^2 + 500(1.01)^59(1.003)
This is a geometric series with the ratio being (1.01/1.003) as each term is changing by this ratio.
n (number of terms) = 60
a (initial value) = 500(1.003)^60
You get A60 = $44, 404.38