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General Thoughts: Mathematics (1 Viewer)

photastic

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part i) i just went screw it and put 10/3 + 10. it's wrong 99% sure

I'm curious about question 13 b)ii too :( im sure i got it wrong
Part i was to find the IMMEDIATE amount, hence, you calculate how much was left from the 1st dose and you add it to the 10mL so it should be 10/3+10 unless we're wrong.
 

chrisdelinet

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part i) i just went screw it and put 10/3 + 10. it's wrong 99% sure

I'm curious about question 13 b)ii too :( im sure i got it wrong
you are right for part i) as the question says amount of drugs right after second dose (somewhere on the lines of this) therefore at end of 1st 8hr period there will be 10/3 mL of drugs within patient (1/3 of drugs present at begining of 8hr period remains). therefore right after second dose, which is when 1st 8hr period ends, you have (10 + 10/3)mL of drugs! you should change your response to 'it's right 99% sure' (well thats what i believe) and for 13b) ii), i believe that is the bearings question, i got 333 degrees for that (seeing that most other people have this and including me, i believe that is quite solid evidence that 333 degrees is correct)
 

stampede

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superannuation q

A60 = 500(1.003)^60 + 500(1.01)(1.003)^59 + ... + 500(1.01)^58(1.003)^2 + 500(1.01)^59(1.003)

This is a geometric series with the ratio being (1.01/1.003) as each term is changing by this ratio.

n (number of terms) = 60

a (initial value) = 500(1.003)^60

You get A60 = $44, 404.38
 

HSC_killer

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with the cut off for a band 6, is the hsc mark counted or is it the raw marks obtained from that exam that will be counted as cutoof of band 6?
 

chrisdelinet

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instead of writting sin D i wrote sin (theta) :( .....am i going to lose all those marks???
hmm i believe you'll lose 1, hard to say because you did not specify the angle, depends if bostes wants to be cruel in a fairly easy test.
 

chrisdelinet

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superannuation q

A60 = 500(1.003)^60 + 500(1.01)(1.003)^59 + ... + 500(1.01)^58(1.003)^2 + 500(1.01)^59(1.003)

This is a geometric series with the ratio being (1.01/1.003) as each term is changing by this ratio.

n (number of terms) = 60

a (initial value) = 500(1.003)^60

You get A60 = $44, 404.38
sorry to pop your bubble, but the question asked for nearest dollar therefore A60 = $44, 404

you may think oh yeah pshhhh, but it's a heads up for people doing the exam in future years READ THE BLOODY QUESTION.
 

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