general UNSW chit-chat (1 Viewer)

MJ-47

Member
Joined
Dec 14, 2007
Messages
101
Location
Kensington
Gender
Male
HSC
2008
Hey chit-chat thread

I was wondering what societies in UNSW are awesome?

And also can someone plz tell me what is involved in being a member of the Athiest Society (like what they get up to and stuff)

Thks...much appreciated :)
 

Omie Jay

gone
Joined
Nov 8, 2006
Messages
6,673
Location
in my own pants
Gender
Female
HSC
2007
Also, to all prospective future unsw students and 'give-me-help-because-i-do-not-know-where-to-find-this-info' people, for the above enquiry i typed into google search: "unsw societies", and the first link i got was the one i posted up.

GOOGLE IS YOUR FRIEND!!!
 

uhawww

Flakes
Joined
Sep 2, 2006
Messages
1,380
Location
Sydney
Gender
Male
HSC
2006
Is it just me or is that wiki really buggy? I really need to edit a page but it's not letting me login or anything... :\
 

tallkid34

In 25 words or less
Joined
Sep 3, 2005
Messages
1,124
Gender
Male
HSC
2006
For some extra sexy time?
If it were for that, I'd long have a double bed. I have 2 beds because my sister sometimes comes back from boarding school and sometimes sleeps in my room.

Anyway, I'm off for a vacation overseas for the next 2 weeks so I won't be around as much (if ever). See you all when I get back.
 

uhawww

Flakes
Joined
Sep 2, 2006
Messages
1,380
Location
Sydney
Gender
Male
HSC
2006
He didn't tell us where he's going... now I'm curious for the next 2 weeks.... :angry:
 

Omie Jay

gone
Joined
Nov 8, 2006
Messages
6,673
Location
in my own pants
Gender
Female
HSC
2007
urrggghh.... math1231 algebra class test tomorrow........

So i just need to confirm/find out how to find out some stuff:

Kernal: ?
Image: ?
Basis: Row reduce, then the number of leading columns?
Dimention: Same thing?
Rank: Same thing.
Nullity: Row reduce, then number of non-leading columns.

Here is my incorrect answers from my second attempt at online question:
http://i397.photobucket.com/albums/pp60/omiejay/q1.jpg
http://i397.photobucket.com/albums/pp60/omiejay/q2.jpg
http://i397.photobucket.com/albums/pp60/omiejay/q4.jpg

4/10, i got 6/10 for first attempt, can someone tell me how to do the ones i got wrong? I at least wanna completely pwn the online tests, give me better chance of passing the course =)
 

Forbidden.

Banned
Joined
Feb 28, 2006
Messages
4,436
Location
Deep trenches of burning HELL
Gender
Male
HSC
2007
@forbidden: buy the usb hub at strathfield car radios. if you live near the kingsford one, im working there on sunday.

and LOL i have cod 4 and 5 both downloaded =)
cod4 is a fun/funny game (except on Veteran difficulty) it is an award winning game its fun to play this game with buddies sometimes during summer


urrggghh.... math1231 algebra class test tomorrow........

So i just need to confirm/find out how to find out some stuff:

Kernal: ?
Image: ?
Basis: Row reduce, then the number of leading columns?
Dimention: Same thing?
Rank: Same thing.
Nullity: Row reduce, then number of non-leading columns.

Here is my incorrect answers from my second attempt at online question:
http://i397.photobucket.com/albums/pp60/omiejay/q1.jpg
http://i397.photobucket.com/albums/pp60/omiejay/q2.jpg
http://i397.photobucket.com/albums/pp60/omiejay/q4.jpg

4/10, i got 6/10 for first attempt, can someone tell me how to do the ones i got wrong? I at least wanna completely pwn the online tests, give me better chance of passing the course =)
If I have time I will post more.

Question 1

(Hint: you don't need to find all the eigenvalues and eigenvectors to answer this question)

^

Timesaver and a real WHOPEEEEEEEEEEEEEE
Anyway I'm pissed off with the forum's LaTeX functionality.


Multiply the 1st and 3rd row by the eigenvector and you get a resultant vector with 4 rows and 1 column.
(You can multiply using all rows if you are confused)

Compare the eigenvector (4 by 1) with the resultant vector (4 by 1 also)
eigenvector times lambda equals the resultant vector.

So solve for lambda! (It wasn't 3!!!)

Remember Avv

Question 4

OH HELL NO it ain't the second choice.
There is a power in one of the variables (the squared).
Next time you see a power in one of the variables avoid it! It is NOT a linear transformation whatsoever!

4th one involving the dot products is also a bad choice.
I received a test question or something proving whether the dot product of two vectors are linear transformations or what not are linear transformations and they aren't apparently. I can't remember proving it.

So choice #1 and #3 seems to be the best choices for you.

They should be more specific with what they teach, this is linear algebra they are teaching not just algebra as a whole (including chaotic systems blah blah)









Omie Jay

are you in the library?
look for me going on bos and looking up the M60 machine gun and other firearms and munitions on Wikipedia
 
Last edited:

Omie Jay

gone
Joined
Nov 8, 2006
Messages
6,673
Location
in my own pants
Gender
Female
HSC
2007
Haha, nah im home. If i was at the library, i'd have my laptop with me, and i'd be downloading assassins creed directors cut, and wanted.

With first question, why do u choose the 1st and 3rd rows? How do u come to that conclusion?
 
Last edited:

Forbidden.

Banned
Joined
Feb 28, 2006
Messages
4,436
Location
Deep trenches of burning HELL
Gender
Male
HSC
2007
Haha, nah im home. If i was at the library, i'd have my laptop with me, and i'd be downloading assassins creed directors cut, and wanted.

With first question, why do u choose the 1st and 3rd rows? How do u come to that conclusion?
lol dling??
the IT department did warn students about copyright infringing shit flowing around here and there.m

the second row is meaningless. there is a zero.
zero times anything equals zero.
wont get an eigenvalue out of that.

i omit the fourth row to save time.

remember the hint they gave you.
 

shoxgeneration

*pamplemousse
Joined
Jan 30, 2006
Messages
393
Gender
Female
HSC
2006
omggg woah when did bos update their profile page interface?!?! haha. im gonna go check mine out and try to snazz it up if bothered!
 

Users Who Are Viewing This Thread (Users: 0, Guests: 1)

Top