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Graph Question (1 Viewer)

sasquatch

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Im working from Fitzpatrick for graphs doing 30c.. For this set of exercises, it asks to find solutions to inequalities using graphs as aids. I have no problem doing that, but what ive noticed is for questions such as:

cos2x > (1/4), 0 <= x <= 2pi

The solution is written as:

0 <= x < pi/3 or 2pi/3 < x < 4pi/3 or 5pi < x <= 2pi

Why is it that at the begging and end parts of the graph bits, erm (0 <= x and the x <= 2pi parts), it is less than or equal... instead of just less than. And why does this only occur when the solution corresponds to parts of the domain given?

Wait.. i just realised that was a stupid question, its because AT zero, and 2 pi, those two points satisfy the inequality....nevermind anybody!
 
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Riviet

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Hehe that's right, just remember to look at the domain, and not the original inequality. ;)
 

sasquatch

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Ok for a different question the answer says:


0 < x < pi/2, execpt pi/4

or

pi < x < 3pi/2, except 5pi/4


I wrote:

0 < x < pi/4, pi/4 < x < pi/2, pi < x < 5pi/4 or 5pi/4 < x < 3pi/2

Thats the same right?
 
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Riviet

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sasquatch said:
Ok for a different question the answer says:


0 < x < pi/2, execpt pi/4

or

pi < x < 3pi/2, except 5pi/4


I wrote:

0 < x < pi/4, pi/4 < x < pi/2, pi < x < 5pi/4 or 5pi/4 < x < 3pi/2

Thats the same right?
Yep that's basically the same thing.
 

sasquatch

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What do you mean write 0? And um... im just gonna write it the way ive done hehe...
 

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