Graphing Question (1 Viewer)

[Praer]

How would you draw a y=log[something]
for example y=log[(2x+1)(x+1)]
Thanks in advance

 

[clintmyster]

Just substitue a range of x values bearing in mind that the [ ] can't be less than or equal to zero.
Once you create a tabe of values go from there and plot.
Make sure to show the asymptote

Should look like this: http://www4a.wolframalpha.com/Calcu...e=image/gif&s=52&w=399&h=187&cdf=RangeControl

 

[Praer]

Alright thanks but what if im not given the equation?

 

[Praer]

And im given a graph instead?

 

[Viscass]

if given a f(x) in y=log(f(x)), use where it equals 0 to draw verticle asymptotes, and where f(x)<0 y=log(f(x)) does not exist so you dont draw anything for those x values, also when f(x)=1 log(f(x))=0

keep in mind that if there is a minimum turning point on the x axis (such as f(x)=x^2 at 0) there a vertical asymptote with values aproaching from y=-infinty from both sides

 

[Praer]

Legend!~
Tnx