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hard Sequence and Series Question!! (1 Viewer)

kevda1st

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Its probably under harder 2unit in extension 1 but here's the question! please help

1,3,6,10,15....are called triangular numbers

Use the formula for the sum of an arithmetic series to find the 30th triangular number.
 

MathsTutorz

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Its probably under harder 2unit in extension 1 but here's the question! please help

1,3,6,10,15....are called triangular numbers

Use the formula for the sum of an arithmetic series to find the 30th triangular number.
1 = 1
3 = 1+2
6 = 1 + 2 + 3
10 = 1 + 2 + 3 + 4

30th number will be

30/2 (2 + 29 x 1 ) = 465
 
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1, 3, 6,10,15,.......

New set of series you can make from top
1+2+3+4+5+6+......
true since 1+2 = T2 from original
1+2+3 = T3 from original
1+2+3+4 = T4 (" ")
so on....

a= 1 n=30 d= 1

s30= 30/2 (2x1+(30-1)x1)
= 15x31
= 465

lol kev, cya
 
Last edited:

orwellstudent

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1, 3, 6,10,15,.......

New set of series you can make from top
1+2+3+4+5+6+......
true since 1+2 = T2 from original
1+2+3 = T3 from original
1+2+3+4 = T4 (" ")
so on....

a= 1 n=30 d= 1

s30= 30/2 (2x1+(30-1)x1)
= 15x31
= 465

lol kev, cya
Sorry, I know this was a post a LOOONNGG time ago but why is d=1? Though you did say you made a replica series with 1+2+3+4+5... but may I ask of how exactly you derived that? If anyone passing this knows, please reach out. I'm sorry if it's a intuitive question, I just don't get the reasoning behind it yet. Thanks! :)
 

InteGrand

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Sorry, I know this was a post a LOOONNGG time ago but why is d=1? Though you did say you made a replica series with 1+2+3+4+5... but may I ask of how exactly you derived that? If anyone passing this knows, please reach out. I'm sorry if it's a intuitive question, I just don't get the reasoning behind it yet. Thanks! :)


(1 layer) T1 = 1:



(2 layers) T2 = 3:

••

(3 layers) T3 = 6:

••
•••

(4 layers) T4 = 10:

••
•••
••••

(5 layers) T5 = 15:

••
•••
••••
•••••,

 
Last edited:

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