Help on intergration (1 Viewer)

[bored of fail 1]

2a i got the exact same working out ... but somehow ... it didn't match lol

whats the answer given

 

[kittyful]

whats the answer given

107.223

 

[bored of fail 1]

Q 3 is easy and thus I wont do it

 

[kittyful]

Q 3 is easy and thus I wont do it

ok

 

[bored of fail 1]

note the actual area you are rotating about the y axis, the volume is actually a cylinder of height 2 and radius 8 but from this cylinder you then subtract the volume of the curve about the y axis ( between y=0 and y=2 )

Volume of cylinder = pi r^2 h

so Volume = pi ( 8^2 ) (2 ) - pi integral (x^2) dy [ integrated from y=0..y=2 ]

now x^(1/3) =y
so x= y^3
x^2 = y^6

so volume = 128 pi - pi integral (y^6) dy [ from y=0..y=2]

you do calculations

thats the only kinda hard one that u wanna look at