the cost of running a car at an average speed of v km/h is given by c= 150 + (v^2 / 80) cents/km. find the average speed, to the nearest km/h, at which the cost of a 500 km trip is a minimum
i derived that, so that i had dc/dv = v/160 , which then i made = 0
v=0....
d^2c/dv^2 = 1/160 > 0 (min)
then what?
i derived that, so that i had dc/dv = v/160 , which then i made = 0
v=0....
d^2c/dv^2 = 1/160 > 0 (min)
then what?