P pascho New Member Joined Dec 1, 2006 Messages 3 Gender Undisclosed HSC 2007 Mar 24, 2007 #1 what is the range of this projectile?
K kony Member Joined Feb 10, 2006 Messages 322 Gender Undisclosed HSC 2007 Mar 24, 2007 #2 the displacement is 50. therefore, 50 = (1/2)(9.8)t^2 work out t. then use range = Ux * t.
P pascho New Member Joined Dec 1, 2006 Messages 3 Gender Undisclosed HSC 2007 Mar 24, 2007 #3 kony said: the displacement is 50. therefore, 50 = (1/2)(9.8)t^2 work out t. then use range = Ux * t. Click to expand... thanks man n what if the cannon ball is shot in an angle of 45 degree
kony said: the displacement is 50. therefore, 50 = (1/2)(9.8)t^2 work out t. then use range = Ux * t. Click to expand... thanks man n what if the cannon ball is shot in an angle of 45 degree
airie airie <3 avatars :) Joined Nov 4, 2005 Messages 1,143 Location in my nest :) Gender Female HSC 2007 Mar 24, 2007 #4 Just replace uy with 60*cos45 degrees = 30rt2 m/s, and ux 60*sin45 degrees = 30rt2 m/s. Then calculate as kony pointed out.
Just replace uy with 60*cos45 degrees = 30rt2 m/s, and ux 60*sin45 degrees = 30rt2 m/s. Then calculate as kony pointed out.