Thanks so much. Same I can't seem to figure out part iii.Hey I'll try to help but I haven't done this for a while.
Yeah so I would appreciate some feedback but I hope this helps
Can u please explain what u did ? I'm confused.9|2^{2n}+6n-1
Set n=79, so
9|2^{158}+6*79-1
=> 9|2^{159}+6*158-2
=> 9|2^{159}+946
=> 9|2^{159}+1+9*105
=> 9|2^{159}+1.
Aaah ok. So my mistake was not looking at it for all multiples of 9 rather than trying to find a single value.9|2^{2n}+6n-1
Set n=79, so
9|2^{158}+6*79-1
=> 9|2^{159}+6*158-2
=> 9|2^{159}+946
=> 9|2^{159}+1+9*105
=> 9|2^{159}+1.
-First line is the result in the previous part, with a=2,b=3.Can u please explain what u did ? I'm confused.
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Z not R but yes. a|b means that there exists an integer c with ac=b, i.e. a divides b.Aaah ok. So my mistake was not looking at it for all multiples of 9 rather than trying to find a single value.
So you've just done
?
Ahhh ok cool. Thanks heaps.Z not R but yes. a|b means that there exists an integer c with ac=b, i.e. a divides b.