loser101
Member
- Joined
- Dec 27, 2007
- Messages
- 393
- Location
- Univeristy Sydney Maths Department
- Gender
- Undisclosed
- HSC
- 2010
Find area of ANY triangle given the 3 sides
[SIZE=-0]<center>A = sqrt [ s * (s - a) * (s - b) * (s - c) ]
Where s = (1 / 2)(a + b + c).
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[SIZE=-0]<center>A = sqrt [ s * (s - a) * (s - b) * (s - c) ]
Where s = (1 / 2)(a + b + c).
Proof: Really quite lovely
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<dl><dd>
</dd></dl> by the law of cosines. From this we get the algebraic statement:
<dl><dd>
.</dd></dl> The altitude of the triangle on base a has length bsin(C), and it follows
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