Horizontal/Vertical Velocity - Help?! (1 Viewer)

[chaarii]

A projectile is fired at a velocity of 50ms-1 at an angle of 30 degreest to the horizontal. Determine the range of the projectile..

I don't seem to be able to get any of the equations right, I don't think I'm subbing the right numbers into the right places...

Any help is appreciated! Thankyou in advance =]

 

[uberturtle]

Try drawing a diagram, it kinda helps

*= multiplication (incase u are confused between my x and multiplication symbol)
-take down to be negative for gravity

Ux = U*Cos@
= 50*Cos 30
=43.3m/s (approx)

Uy =U*Sin@
=50*Sin30
=25m/s

For Time of Flight:
At the max height point V=0. THis is at T/2=
V=Uy+at
0=25-9.8t
t=2.55
t=T/2
therefore
T=5.1s

Range= Horizontal Velocity x Time of Flight
R=Ux * T
=43.3*5.1
=220.9183673
=221m (nearest m)

In exams you don't have to go into that much detail, jsut wrote it so u might understand haha.

 

[chaarii]

Argh! I get it!!

Thankyou so much!
Legend to the maxx!!
Your my new best friend LOL

Thanks again!!

 

[Forbidden.]

Kids,
in your study of Mechanics and Kinematics in Physics, please note that the horizontal and vertical motion of an object are independant of each other.
One is subject to constant downward acceleration and the other doesn't have constant acceleration.

 

[jcurry]

just had my physics half yearly today and that exact same question was in it but it went on further than just the range
it was pretty easy though the exam