How far below the x-axis is the beam when x=0? (1 Viewer)

danz90

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lol i think me the idiot wrote,

it is -k5b^4/12 units below or whatever, when x=0

i hope they don't penalise me for putting that minus.
maybe i took the minus away who knows
 

sparkerasp

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I got a bit stuck halfway through this question :( Oh well, no use worrying.
 

r.uss

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I think they're actually going to have to start taking marks off for putting minuses in the wrong places etc. because that is the only way they'll be able to differentiate between everyone.

I've heard that occasionally they become lenient towards the end because just about nobody usually gets them fully out, so the criteria is flexible. But in this case, I dont think they will!
 

anonomis

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ipod21 said:
i left my answer as y= - k5b^4/12

im wrong casue i left it like that...fuck!
y is that wrong? i did the same thing i think
 

mitchellstama

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sub in x = b and y = 0 to find c...the first 2 posts have the right answer but i gt it wrong :angry:
 

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