!How to find the exact area of this region? (1 Viewer)

fabl

Member
Joined
Aug 7, 2014
Messages
56
Gender
Male
HSC
2014
How to find the exact area of this region that lies below 1/ (4x^2 +1) and above 1/(x^2 +4)?
 

photastic

Well-Known Member
Joined
Feb 11, 2013
Messages
1,848
Gender
Male
HSC
2014
First graph the two functions to see which one is the top and bottom function and also the point of intersection. In this, the point of intersections are 1 and 1, by solving for x and in this region, the first function is above the second function.

So solve a definite integral between -1 and 1 for 1/ (4x^2 +1) minus 1/(x^2 +4). Or since they are both even functions, you can also multiply the definite integral between 0 and 1 for 1/ (4x^2 +1) minus 1/(x^2 +4) by 2.

Ceebs doing it myself but the link is the integral working out.

https://www.symbolab.com/solver/def...x^{2}+1}-\frac{1}{x^{2}+4}dx/?origin=enterkey
 
Last edited:

Users Who Are Viewing This Thread (Users: 0, Guests: 1)

Top